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Dominik [7]
4 years ago
9

What are the coordinates of the image of L for a dilation with center (0,0) and scale factor 4?

Mathematics
1 answer:
vladimir2022 [97]4 years ago
6 0

Answer:

c) 12,20

Step-by-step explanation:

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Evaluate 5+3^x for (a) x=-2 and (b) x=3 . Write your answers in simplest form.
alexdok [17]

Answer:

a: 3 to the power of -2 is 1/9 = 5 1/9

b: 3 to the power of 3 = 27

5+27 = 32

Step-by-step explanation:

7 0
2 years ago
A block of marble is in the shape of a rectangular prism. The block is 8 feet long, 2 feet wide, and 78 inches high. What is the
Komok [63]
Length of the block of marble in question is (l) = 8 feet
Width of the block of marble in question is (w) = 2 feet
Height of the block of marble in question is (h) = 78 inches
We already know that
1 inch = 0.08 foot
So
Height of the block of marble in question (h) = 78 * 0.08 foot
                                                                       = 6.24 feet
Then
Volume of the marble block = i * w * h
                                             = 8 * 2 * 6.24 cubic feet
                                             = 99.84 cubic feet
From the above dduction we can conclude that the volume of the marble block in the shape of a rectangular prism is 99.84 cubic feet.
7 0
3 years ago
If u(x) = x^5 - x^4 + x^2 and v(x) = -x^2, which expression is equivalent to (u/v)(x)
Alchen [17]
\dfrac{u(x)}{v(x)}=\dfrac{x^5-x^4+x^2}{-x^2}=\dfrac{x^5}{-x^2}-\dfrac{x^4}{-x^2}+\dfrac{x^2}{-x^2}\\\\=-x^3+x^2-1

The appropriate choice is ...
  C) -x^3 + x^2 - 1
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=-0.2%5Csqrt%7Bx%5E2%7D" id="TexFormula1" title="-0.2\sqrt{x^2}" alt="-0.2\sqrt{x^2}" align="ab
madreJ [45]

Answer:

The simplified answer to that is -0.2x.

Hope this helps and if you could mark this as brainliest. Thanks!

6 0
3 years ago
Read 2 more answers
The mass of a particular substance is known to grow exponentially at a rate of 1.5% per day. Its initial mass was 230 grams and,
Papessa [141]

Answer:

23 days

Step-by-step explanation:

Given that the mass of a particular substance is known to grow exponentially at a rate of 1.5% per day

Initial mass = 230 gm

After t days, mass = 325 gm

The equation is

P(t) = 325 = 230 (1+\frac{1.5}{100} )^t\\\frac{325}{230} =1.015^t\\log 1.413 = t log 1.015\\t = \frac{log 1.413}{log 1.015} =\frac{0.1502}{0.0065} \\=23.229

Approximately after 23 days the mass will become 325 gms.

7 0
4 years ago
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