Answer:
a) dy/dx = 4/(2y+1)^2.
(b) y = 4/9 x - 14/9
(c) d2y/dx2 = -64/243
Step-by-step explanation:
You have the following equation
(1)
(a) You first derivative implicitly the equation (1) respect to x:
next, you solve the last result for dy/dx:
(2)
(b) The equation for the tangent line is given by:
(3)
with yo = -2 and xo = -1
To find the slope m you use the result of the equation (2), because dy/dx evaluated in (-1,-2) is the slope at such point:
m =
Hence, by replacing in the equation (3) you obtain:
hence, the equation for the tangent line is y = 4/9 x - 14/9
(c) To find d2y/dx2 you derivative the result obtain in the equation (2):
(4)
the second derivative for the point (-1,-2) is obtained by replacing y=-2 and dy/dx=m=4/9 in the equation (4):
hence, d2y/dx2 evaluated in (-1,-2) is -64/243
Step-by-step explanation:
Answer:
2greater then or equal to x 5 greater then or equal to
The correct answer for the question that is being presented above is this one: "2(x - 1)(3x + 4) = 0."
<span>6x 2 + 2x - 8 = 0
(2x - 2) (3x + 4) = 0
2(x - 1)(3x + 4) = 0
The correct answer for the question that is being presented above is this one: "</span><span>(x - 4)^2 = -19."</span><span>
x2 - 8x + 3 =0
x2 - 8x + 16 = -3 - 16
(x - 4)(x - 4) = -19
(x - 4)^2 = -19</span>
Usual limit of sin is sinX/X--->1, when X--->0
sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0
