Question

During a football game a concert in stenciled family three hamburgers and two white dogs for a total of $13 and another family two hamburgers and five hotdogs for a $ $16 what are the prices of a hamburger and a hotdog

Answer 1

Answer:

Price of  hamburgers = $2

Price of white-dogs = $3

Step-by-step explanation:

Let

The number price of hamburgers be x

The number price of white-dogs  be  y

Then the first family buys 3 hamburgers and 2 white -dogs for $13

3x + 2y = 13-----------------------------(1)

Another first family buys 2 hamburgers and 5 white -dogs for $16

2x + 5y = 16----------------------------(2)

To solve let us multiply eq(1) by 2 and eq(2) by 3, we get

6x + 4y = 26-----------------------------(3)

6x + 15y = 48----------------------------(4)

subracting (3) from (4)

6x + 15y = 48

6x + 4y = 26

(-)

-------------------------

        11y  = 22

---------------------------

$y =\frac{22}{11}$

y =2

Now substituting the value of y in eq(1),

3x + 2(2) = 13

3x + 4 = 13

3x = 13-4

3x = 9

x =$\frac{9}{3}$

x =3