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nordsb [41]
3 years ago
11

You bought a large container of fruit punch. The label on the container says there are 128 fluid ounces of fruit punch in the co

ntainer. How many cups is that?
Mathematics
2 answers:
coldgirl [10]3 years ago
7 0
1 cup=8oz
ratio
1:8=x:128
1/8=x/128
multiply both sides by 128
128/8=x
16=x

16 cups
Sedbober [7]3 years ago
7 0

Answer:

16 cups.

Step-by-step explanation:

It is given that a large container of fruit punch contains 128 fluid ounces of fruit punch in it.

We know that

8 fluid ounces = 1 cup

Divide both sides by 8.

1 fluid ounces = 1/8 cup

Now multiply both sides by 128

128× 1 fluid ounces = 128\times \frac{1}{8} cup

128 fluid ounces = 16 cup

Since container of fruit punch contains 128 fluid ounces of fruit punch in it, therefore there 16 cups of fruit punch in the container.

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Mhanifa u helped me with this question.... U said it was 25 and its not so why is it wrong
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Hey I don't know who Mhanifa is but 25 is correct, and I will put the entire explanation to how to get the answer here.

First of all the 2 lines on the left and right side of the triangles are means that those 2 lines are equal and thus forming a isosceles triangle.

This means that the bottom right angle is also 2x+2 degrees.

Now because all 3 angles in a triangle adds to 180 degrees, we can set up equation.

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A square is cut diagonally into two equal parts. If each part has an area of 50 cm2, then what is the perimeter of each part?
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Step-by-step explanation:

Given data

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Solve the system by using elementary row operations on the equations. Follow the systematic elimination procedure
Umnica [9.8K]

Answer:

The solution of the Given matrix

  ( x₁ ,    x ₂ ) = ( - 5 , 4 )

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equations are  x₁+4 x₂ = 11 ...(i)

                                 2 x₁ + 7 x₂= 18 ...(ii)

The matrix form

                                A X = B

            \left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]

<u>Step(ii):-</u>

      \left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]

The Augmented Matrix form is

[AB] = \left[\begin{array}{ccc}1&4&11\\2&7&18\\\end{array}\right]

Apply Row operations,  R₂ → R₂-2 R₁

[AB] = \left[\begin{array}{ccc}1&4&11\\0&-1&-4\\\end{array}\right]  

The matrix form

                   \left[\begin{array}{ccc}1&4\\0&-1\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\-4\\\end{array}\right]

The equations are

                     x₁ + 4 x₂ = 11 ...(a)

                         - x ₂ = - 4

                            x ₂ = 4

Substitute   x ₂ = 4 in equation (a)

                      x₁ + 4 x₂ = 11

                      x₁ = 11 - 16

                        x₁ = -5

<u>Final answer</u>:-

The solution of the Given matrix

  ( x₁ ,    x ₂ ) = ( - 5 , 4 )

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