Answer:
24.56 (parallelogram)
Step-by-step explanation:
4 sides of ABCD: AB, BC, AD, DC
perimeter = AB + BC + AD + DC
distance of two points: √(x-x')²+(y-y')²
AB = √3²+4² = √25 = 5
BC = √7²+2² = √53 = 7.28
AD = √7²+2² = √53 = 7.28
DC = √3²+4² = √25 = 5
P = 5*2 + 7.28*2 = 24.56
Answer:
x < -2.5 and x > 1
Step-by-step explanation:
Answer:
If Dominic buys 2 points (2% of the loan value) he will get a better rate and hence less payment. The question is asking how long will it take him to save the initial investment of 2% of the loan value due to a smaller payment. The monthly payment at 5.45% is $1,146.43, the monthly payment for 5.2% is $1,118.66. This is a difference of $27.77 per month. The 2 points will cost him $3,752.00. The question is asking how long will it take Dominic to re-coup his $3,752.00 if he saves $27.77 per month. Just divide the 2 numbers and you get 135.10 months. If you divide that by 12 you get 11.26 years, which is roughly 11 years, 4 months.
Step-by-step explanation:
Here is what the question is asking. If Dominic buys 2 points (2% of the loan value) he will get a better rate and hence less payment. The question is asking how long will it take him to save the initial investment of 2% of the loan value due to a smaller payment. The monthly payment at 5.45% is $1,146.43, the monthly payment for 5.2% is $1,118.66. This is a difference of $27.77 per month. The 2 points will cost him $3,752.00. The question is asking how long will it take Dominic to re-coup his $3,752.00 if he saves $27.77 per month. Just divide the 2 numbers and you get 135.10 months. If you divide that by 12 you get 11.26 years, which is roughly 11 years, 4 months.
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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