Answer:
Option D
Step-by-step explanation:
Option D is not proper scientific notation, as the exponent is not on the 10
We use the SSS congruence rule to prove the triangles to be congruent. From there, we then use CPCTC to show that angle I is congruent to angle L.
This is shown in the two column table (attached image below)
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Notes:
SSS = side side side
CPCTC = corresponding parts of congruent triangles are congruent
Answer:
a) Because the confidence interval does not include 0 it appears that there
is a significant difference between the mean level of hemoglobin in women and the mean level of hemoglobin in men.
b)There is 95% confidence that the interval from −1.76 g/dL<μ1−μ2<−1.62 g/dL actually contains the value of the difference between the two population means μ1−μ2
c) 1.62 < μ1−μ2< 1.76
Step-by-step explanation:
a) What does the confidence interval suggest about equality of the mean hemoglobin level in women and the mean hemoglobin level in men?
Given:
95% confidence interval for the difference between the two population means:
−1.76g/dL< μ1−μ2 < −1.62g/dL
population 1 = measures from women
population 2 = measures from men
Solution:
a)
The given confidence interval has upper and lower bound of 1-62 and -1.76. This confidence interval does not contain 0. This shows that the population means difference is not likely to be 0. Thus the confidence interval implies that the mean hemoglobin level in women and the mean hemoglobin level in men is not equal and that the women are likely to have less hemoglobin than men. This depicts that there is significant difference between mean hemoglobin level in women and the mean hemoglobin level in men.
b)
There is 95% confidence that the interval −1.76 g/dL<μ1−μ2<−1.62 g/dL actually contains the value of the difference between the two population means μ1−μ2.
c)
If we interchange men and women then
- confidence interval range sign will become positive.
- μ1 becomes the population mean of the hemoglobin level in men
- μ2 becomes the population mean of the hemoglobin level in women
- So confidence interval becomes:
1.62 g/dL<μ1−μ2<1.76 g/dL.
F(x)=2+3sin(theta)
f'(x)=3cos(theta)
To find the slope you need the value of theta. The general formula is:
y-f(xo)=f'(xo)-(x-xo)
Add them around 8 and -4 for smallest and around 1 + 3 and 2 + 8 for highest
