What is the vertex of g(x) = 8x2 - 64x
1 answer:
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Answer:
72
Step-by-step explanation:
The area (A) of a rhombus is calculated as
A = × d₁ × d₂ (d₁ and d₂ are the diagonals )
The diagonals bisect each other at right angles
d₁ = 2 × 6 = 12
Use the tangent ration in the upper left right triangle and the exact value
tan60° =
tan60° = =
=
( multiply both sides by 6 )
opp = 6 , then
d₂ = 2 × 6 = 12
Thus
A = × 12 × 12
= 6 × 12
= 72
To solve this we are going to use the average rate of change formula: 
where
is the average rate of change of the function
is the position function evaluated at 
is the position function evaluated at 
is the first point in the interval
is the second point in the interval
We can infer for our problem that the first point is 3 and the second point is 6, so
and 
. Lets replace those values in our formula:
We can conclude that the average rate of change of the function f(x) = 1 x - x2 - 2 for <span>3 ≤ x ≤ 6 is -8</span>
where
We can infer for our problem that the first point is 3 and the second point is 6, so
We can conclude that the average rate of change of the function f(x) = 1 x - x2 - 2 for <span>3 ≤ x ≤ 6 is -8</span>