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dolphi86 [110]
2 years ago
12

Multiple Choice: Choose the correct simplified expression for (3x - y) (W+p-3).

Mathematics
2 answers:
murzikaleks [220]2 years ago
8 0

Answer:

answer this 5-y this the answer thanks for

Mariulka [41]2 years ago
7 0

Answer:

3xw+3xp+3y-9x-yw-yp

(I have no idea how it's ordered on your test)

Step-by-step explanation:

(3x-y)(w+p-3)

Multiply.

3xw+3xp-9x-yw-yp+3y

Reorder.

3xw+3xp+3y-9x-yw-yp

(me looking at this long a** expression like o.O)

---

hope it hope

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A brand of uncooked spaghetti comes in a box that is a rectangular prism with a length of 8 inches, a width of 2 inches, and a h
garik1379 [7]

Answer:

24 sq inches. Hope this helps :)

Step-by-step explanation:

4 0
3 years ago
Find the surface area of the regular pyramid.
spayn [35]

Answer:

Answer = 93.6

Step-by-step explanation:

frist multipy 9 x 13 to get 117 than divided it by 2 = 58.5, than times it by 3 since there is three sides.

(58.5 x 3 is 175.5)      

Than for the base multipy 7.8 x 9 = 70.2, but since its a tri, divided it by 2 = 35.1.

Add 58.5 and 35.1 to get 93.6

5 0
2 years ago
Read 2 more answers
A hockey puck has a diameter of 3 inches and rolls on its edge for 24 rotations. How far did it roll before falling flat?
scoundrel [369]

Find the circumference of the puck using circumference = pi x diameter

Circumference = 3.14 x 3 = 9.42 inches.

For every rotation the puck would travel 9.42 inches.

Now multiply y by 24 rotations:

9.42 x 24 = 226.08 inches.

Answer: 226.08 inches

4 0
3 years ago
Find the integral using substitution or a formula.
Nadusha1986 [10]
\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx

Derivative of the denominator:
\rm (x^2+2x+5)'=2x+2

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx

and then split the fraction,

\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx

Based on our previous test, we know that a simple substitution will work for the first integral: \rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx

So the first integral changes,

\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx

integrating to a log,

\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2

So we have this going on,

\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx

Bringing all that stuff together as a single square,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx

Making the substitution: \rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx

giving us,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du

simplying a lil bit,

\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du

and hopefully from this point you recognize your arctangent integral,

\rm ln|x^2+2x+5|+\frac52arctan(u)

undo your substitution as a final step,
and include a constant of integration,

\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c

Hope that helps!
Lemme know if any steps were too confusing.

8 0
3 years ago
It takes 16 minutes for 9 people to paint 8 walls . How many minutes does it take for 4 people to paint 6 walls?
Soloha48 [4]

Answer:

27 minutes to complete the painting of 4 walls

Step-by-step explanation:

since 16m with 9p --> 8 walls

x minutes with 4p --> 6 walls?

let x= minutes

6 walls painted=(8/144 walls painted per minute)x

simplify

x= 6 divided by (8/144)

x=108 minutes (to complete 6 walls)

108/4=

27 minutes to complete the painting of 4 walls

4 0
3 years ago
Read 2 more answers
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