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tino4ka555 [31]
3 years ago
13

Round the numbers in each expression to the nearest whole number. Then select all expressions that are about 8. A. 3 1 5 + 5 7 9

B. 15 5 7 − 8 2 9 C. 1 5 8 + 5 2 5 D. 10 1 4 − 1 11 15 E. 2 7 10 + 4 8 9
Mathematics
1 answer:
Aleksandr [31]3 years ago
4 0

Answer:

B. 1557 − 829

Step-by-step explanation:

A. 315 + 579 = 894

B. 1557 − 829 = 728

C. 158 + 525 = 683

D. 1014 − 11115 = - 10101

E. 2710 + 489 = 2221

from the expression above the only expression that is about 8  which means that the expression that 8 will subdivide without a reminder which is 728

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MaRussiya [10]
<h3 /><h3>3(1 - 3x) =  - 7 + x \\ 3 - 9x =  - 7    + x \\ 3 + 7 = x + 9x \\ 10 = 10x \\ x =  \frac{10}{10}  \\ x = 1</h3>

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em><em> ❤️</em><em>✌ </em>

8 0
2 years ago
What is the domain of (-2, 5), (8, 6), (3, 12) (2, 6)
lord [1]

Answer:

The domain is (-2, 8, 3, 2)

Step-by-step explanation:

The domain is such because domain is the x-element or the one you see at first in the ordered pairs.

4 0
2 years ago
What is average unit rate for 200/12.54
Nadusha1986 [10]

Answer:

Approximately 16.

Step-by-step explanation:

If you just divide 200/12.54, you get about 15.9 which rounds to 16.

3 0
3 years ago
Find the number of the different ways, for 3 students to sit on 7 seats in one row.
qwelly [4]

Answer:

210

Step-by-step explanation:

Here comes the problem from Combination.

We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.

Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7

Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6

Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5

Hence the total number of ways for three students to be seated will be

7 x 6 x 5

=210

3 0
3 years ago
Read 2 more answers
In 2011, the Institute of Medicine (IOM), a non-profit group affiliated with the Select one US National Academy of Sciences, rev
Sergio [31]

Answer:

B. Yes, there are at least 10 people with weak bones and 10 people with strong bones in each group.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

The correct answer is:

B. Yes, there are at least 10 people with weak bones and 10 people with strong bones in each group.

7 0
3 years ago
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