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Gekata [30.6K]
3 years ago
9

What is the answer for this linear equation: (3x-6)+(2x+9)

Mathematics
2 answers:
just olya [345]3 years ago
6 0

Answer:

It's not a linear equation. It,s an algebraic expression

Step-by-step explanation:

3x-6+2x+9 =5x+3

ale4655 [162]3 years ago
5 0

Because there is no equal sign, we can't know or find what x =. We can only simplify by adding like terms.

3x + 2x = 5x

-6 + 9 = 3

5x + 3 is the simplified answer.

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What’s the slope of this equation
Vinvika [58]

Answer:

<em>m</em> = -2

General Formulas and Concepts:

<u>Algebra</u><em><u> </u></em><u>I</u>

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Function y = -2x + 5

<u>Step 2: Break Function</u>

Slope <em>m</em> = -2

y-intercept <em>b</em> = 5

5 0
3 years ago
A gumball machine has contains orange,yellow,and purple gum balls is 3 over 4.the probability of getting a yellow gum ball is 1
stich3 [128]
4 out of 10 because you add 1 +3 that equals 4 and then add6+4=10=4 out of10
6 0
3 years ago
It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

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3 years ago
What is the oblique asymptote of the function f(x) = the quantity of x squared plus x minus 2, all over x plus 1
Korvikt [17]
Hello,

y=ax+b is the asymptote
with
$a=  \lim_{n \to \infty}  \frac{f(x)}{x}=\lim_{n \to \infty}  \dfrac{x^2+x-2}{x^2+x}=1\\\\&#10;
$b= \lim_{n \to \infty} f(x)-ax= \lim_{n \to \infty} \frac{x^2+x-2}{x+1}-x= \lim_{n \to \infty} \frac{-2}{x+1}=0  $

7 0
3 years ago
Need help geometry question central angles and arcs?
Maksim231197 [3]

Answer:

135

Step-by-step explanation:

360-90=270

270/2=135

7 0
3 years ago
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