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3 years ago

I need help with 6 please

Mathematics

1 answer:

kari74 [83]3 years ago

8 0

The $3.92 for 8 ounces is the most expensive

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Which of the following shows all of the factor pairs of 28?

kow [346]

The factor pairs of a number when multiplied give the original number.

Therefore, all the factor pairs of 28 are:

$\begin{gathered} 1\times28; \\ 2\times14; \\ 4\times7 \end{gathered}$

The correct choice is the first one

4 0

2 years ago

Find the area of the shaded region.

taurus [48]

Answer:

$426.96 \: {km}^{2}$

Step-by-step explanation:

Area of the shaded region = Area of triangle with base 40 km and height 27 km - Area of circle with radius (12/2) 6 km.

$= \frac{1}{2} \times 40 \times 27 - 3.14 \times {(6)}^{2} \\ \\ = 20 \times 27 - 3.14 \times 36 \\ \\ = 540 - 113.04 \\ \\ = 426.96 \: {km}^{2}$

5 0

3 years ago

Express 5n+2 - 51+1 – 5" in<br>the simplest form.

saw5 [17]

Answer:

Step-by-step explanation:

5n-53

Hope it helps

Mark me as brainiest pls begging you

7 0

3 years ago

What is 43 x 34/ 28-14= <br> this /stands for a division sine

Sergio [31]

This is the answer 104.4285714285714

6 0

3 years ago

A new experimental strain of pepper plants was being studied to estimate how much fruit one plant would produce in a typical gro

zmey [24]

Answer:

58.9% produced produced peppers weighing between 13 and 16 pounds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 15

Standard Deviation, σ = 1.75

We are given that the distribution of weight of peppers is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(peppers weighing between 13 and 16 pounds)

$P(13 \leq x \leq 16) = P(\displaystyle\frac{13 - 15}{1.75} \leq z \leq \displaystyle\frac{16-15}{1.75}) = P(-1.142\leq z \leq 0.571)\\\\= P(z \leq 0.571) - P(z < -1.142)\\= 0.716 - 0.127 = 0.589 = 58.9\%$

$P(13 \leq x \leq 16) = 58.9\%$

58.9% produced produced peppers weighing between 13 and 16 pounds.

7 0

4 years ago