Question

Can someone help me with these 5 question I have attached?

Answer 1

Example 2: x=10

Example 3: x=-1

Example 4: x=35

Example 5: a-b+c=9

Example 6: x=1, x=1/2

Further explanation:

Example 2:

$\sqrt{4x-4} =6$

Taking Square on both sides

$(\sqrt{4x-4})^2 =(6)^2\\4x-4=36\\4x=36+4\\4x=40\\\frac{4x}{4}=\frac{40}{4}\\x=10$

Example 3:

$9+\sqrt{4x+8}=11$

Subtracting 9 from both sides

$9-9+\sqrt{4x+8}=11-9\\\sqrt{4x+8}=2$

Taking Square on both sides

$(\sqrt{4x+8})^2=(2)^2\\4x+8=4\\4x=4-8\\4x=-4\\\frac{4x}{4}=-\frac{4}{4}\\x=-1$

Example 4:

$8+\sqrt{x+1}=2$

subtracting 8 from both sides

$8-8+\sqrt{x+1}=2-8\\\sqrt{x+1}=-6$

Taking Square on both sides

$(\sqrt{x+1})^2=(-6)^2\\x+1=36$

Subtracting 1 from both sides

$x+1-1=36-1\\x=35$

Example 5:

$\sqrt{a-b+c}=3$

Taking Square on both sides

$(\sqrt{a-b+c})^2=(3)^2\\a-b+c=9$

Example 6:

$2\sqrt{2x-1}=4x-2$

Taking square on both sides

$(2\sqrt{2x-1})^2=(4x-2)^2\\4(2x-1)=16x^2+4-16x\\8x-4=16x^2-16x+4\\8x=16x^2-16x+4+4\\8x=16x^2-16x+8\\16x^2-16x-8x+8=0\\16x^2-24x+8=0$

dividng whole equation by 8

$2x^2-3x+1=0\\2x^2-2x-x+1=\\2x(x-1)-1(x-1)=0\\(2x-1)(x-1)=0\\2x-1=0 => x=\frac{1}{2}\\x-1=0 => x=1$

Keywords: Radical Expressions, Examples

Learn more about radical expressions at:

• brainly.com/question/8145673
• brainly.com/question/10071175

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