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Alex787 [66]
3 years ago
8

Which statement is true out of the value of money that you save increases over time , the value of money remains constant over t

ime, or the present value of money is greater than its future value?
Mathematics
1 answer:
Nataly_w [17]3 years ago
3 0
None is necessarily true.

Even though you have your money in an interest-bearing savings vehicle, its value (purchasing power) may actually decrease if the interest rate is not at least as great as the inflation rate.

In periods of inflation, the value of money decreases over time. In periods of deflation, the value of money increases over time. It tends to be difficult to regulate an economy so the value of money remains constant over time.

The present value of money is greater than the future value in inflationary times. The opposite is true in deflationary times.

_____
In the US in the middle of the last century, inflation rates were consistently 2-3% per year and savings interest rates were perhaps 4-6%. Money saved actually increased in value, and the present value of money was greater than the future value. These days, inflation is perhaps a little lower, but savings interest rates are a lot lower, so savings does not outpace inflation the way it did. The truth or falsity of all these statements depends on where and when you're talking about.
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Find the average velocity of the function over the given interval.
snow_lady [41]

Answer:

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given function y = 3/x -2 ...(i)

The average velocity of the function over the given interval

             Average velocity  = \frac{1}{b-a} \int\limits^b_a {(\frac{3}{x} -2)} \, dx

                               =    \frac{1}{7-4} \int\limits^7_4 {(\frac{3}{x} -2)} \, dx

now integrating

                           =   \frac{1}{3}( \int\limits^7_4 {(\frac{3}{x} )} \, dx-2\int\limits^7_4 {1} \, dx )

                           = \frac{1}{3} (3 (log x) - 2 x )_{4} ^{7}

                        =   \frac{1}{3}( (3 (log 7) - 14 )-(3 log 4 -8))

by using formulas

                 log a-log b = log(a/b)

  on simplification , we get                  

                 = \frac{1}{3}( (3 (log 7) -3 log 4 ) - \frac{1}{3} (6)

                = log(\frac{7}{4} ) -2

Average velocity of the function over the given interval

              =  log(\frac{7}{4} ) -2

 

 

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On Monday, Sarah has to meet her friend at the park after school The distance from her house to school is 2x+5 The distance from
DanielleElmas [232]

Answer:

8x + 4 - z

Step-by-step explanation:

Given the following :

The distance from her house to school is 2x+5 The distance from the school to the park is z If the total distance she was that day is 10x +9 how far is it from the park back to her

Distance from house to school = 2x + 5

Distance from school to park = z

Total distance covered = 10x + 9

Distance from park to house =?

Total distance = (distance from house to school + distance from school to park + distance from park to house)

Let p = distance from park to house

10x + 9 = (2x + 5 + z + p)

10x + 9 - 2x - 5 - z = p

8x + 4 - z

6 0
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