B.
Let's simply look at each conjecture and determine if it's true or false.
A. 2n– 1 is odd if n is positive: Since n is an integer, 2n will
always be even. And an even number minus 1 is always odd. Doesn't matter
if n is positive or not. So this conjecture is true.
B. 2n– 1 is always even: Once again, 2n will always be even. So 2n-1 will always be odd. This conjecture is false.
C. 2n– 1 is odd if n is even: 2n is always even, so 2n-1 will always
be odd, regardless of what n is. So this conjecture is true.
D. 2n– 1 is always odd: 2n will always be even. So 2n-1 will always be odd. Once again, this conjecture is true.
Of the 4 conjectures above, only conjecture B is false. So the answer is B.
Given that the population can be modeled by P=22000+125t, to get the number of years after which the population will be 26000, we proceed as follows:
P=26000
substituting this in the model we get:
26000=22000+125t
solving for t we get:
t=4000/125
t=32
therefore t=32 years
This means it will take 32 years for the population to be 32 years. Thus the year in the year 2032
Answer:
13
Step-by-step explanation:
Replace X with 2
Evaluate the function. g(x) = 3x^2 – 2x + 5 Find f(2)
g(x) = 3(2)^2 – 2(2) + 5
Next conduct PEMDAS
Exponents are first so solve 2^2 which is 2 x 2 = 4
g(x) = 3(4) – 2(2) + 5
Next step is multiplication multiply 3 x 4 and 2x2
g(x) = 12 – 4 + 5
conduct adding and subtracting left from right
g(x) = 13
Answer:
x=-2
Step-by-step explanation:
-4x - 8 = -4 • (x + 2)
Answer: the picture is blurry but it would be the third option. One box out of three shaded.
Step-by-step explanation:
33 1/3 is one third of 100.
Choose the picture that has 1 out of three boxes shaded. This would represent one third.
