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vitfil [10]
2 years ago
14

100 Points!!!! Please HELP!!!

Mathematics
1 answer:
Degger [83]2 years ago
5 0

Answer:

We can use the <u>tan trig ratio</u> to calculate the steepness of each run.

The side <em>opposite</em> the angle is the <em>vertical </em>distance of each path.

The side <em>adjacent </em>to the angle is the <em>horizontal </em>distance of each path.

(see attached diagram)

<u>Tan trig ratios</u>

\sf \tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

<u>Little Thunder</u>

\implies \sf \tan(\theta)=\dfrac{2}{7}

\implies \sf \theta=\tan^{-1}\left(\dfrac{2}{7}\right)

\implies \sf \theta=16^{\circ} \: (nearest\:degree)

Rating = EASY (green circle)

<u>Dodge Ridge</u>

\implies \sf \tan(\theta)=\dfrac{4}{6}=\dfrac{2}{3}

\implies \sf \theta=\tan^{-1}\left(\dfrac{2}{3}\right)

\implies \sf \theta=34^{\circ} \: (nearest\:degree)

Rating = MODERATE (blue square)

<u>Wild Side</u>

\implies \sf \tan(\theta)=\dfrac{4}{4}=1

\implies \sf \theta=\tan^{-1}(1)

\implies \sf \theta=45^{\circ}

Rating = DIFFICULT (black diamond)

<u>Pacific Crest</u>

\implies \sf \tan(\theta)=\dfrac{4}{8}=\dfrac{1}{2}

\implies \sf \theta=\tan^{-1}\left(\dfrac{1}{2}\right)

\implies \sf \theta=27^{\circ} \: (nearest\:degree)

Rating = EASY (green circle)

<u>Thunderbolt</u>

\implies \sf \tan(\theta)=\dfrac{6}{2}=3

\implies \sf \theta=\tan^{-1}(3)

\implies \sf \theta=72^{\circ} \: (nearest\:degree)

Rating = DIFFICULT (black diamond)

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You're conducting a significance test for H0 : p = .35, Ha : p &lt; .35. In a sample of size 40, you identify a count of 11 succ
nordsb [41]

Answer: c. –1 and .1587

Step-by-step explanation:

As per given , we have

Null hypothesis : H_0 : p= 0.35

Alternative hypothesis :  H_1 : p< 0.35

Since Alternative hypothesis is left-tailed ,so the test must be a left tailed test .

Z -Test statistic for proportion = z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

, where p= population proportion

\hat{p} = sample proportions

n= Sample size.

Let x be the number of successes.

For n= 40 and x= 11

\hat{p}=\dfrac{x}{n}=\dfrac{11}{40}=0.275

Then ,  z=\dfrac{0.275-0.35}{\sqrt{\dfrac{0.35(1-0.35)}{40}}}

z=\dfrac{-0.075}{\sqrt{0.0056875}}

z=\dfrac{-0.075}{0.075415515645}

z=-0.99449031619\approx-1

By using z-table ,

P-value for left-tailed test = P(z<-1)= 1-P(z<1)    [∵ P(Z<-z)= 1-P(Z<z) ]

= 1-0.8413

=0.1587

Hence, the -score and P-value are  <u>–1 and 0.1587</u> .

So the correct option is c. –1 and .1587

8 0
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A Turtle traveled 1/10 mile in 1/2 hour. What was the turtle’s rate in miles per hour?
AnnZ [28]
1/5

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Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?
Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

sec^4 x + sec^2 x tan^2 x - 2 tan^4 x

Required

Simplify

(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2

Represent sec^2x with a

Represent tan^2x with b

The expression becomes

a^2 + ab- 2 b^2

Factorize

a^2 + 2ab -ab- 2 b^2

a(a + 2b) -b(a+ 2 b)

(a -b) (a+ 2 b)

Recall that

a = sec^2x

b = tan^2x

The expression (a -b) (a+ 2 b) becomes

(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

..............................................................................................................................

In trigonometry

sec^2x =1  +tan^2x

Subtract tan^2x from both sides

sec^2x - tan^2x =1  +tan^2x - tan^2x

sec^2x - tan^2x =1

..............................................................................................................................

Substitute 1 for sec^2x - tan^2x in (sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

(1) (sec^2x+ 2 tan^2x)

Open Bracket

sec^2x+ 2 tan^2x ------------------This is an equivalence

(secx)^2+ 2 (tanx)^2

Solving further;

................................................................................................................................

In trigonometry

secx = \frac{1}{cosx}

tanx = \frac{sinx}{cosx}

Substitute the expressions for secx and tanx

................................................................................................................................

(secx)^2+ 2 (tanx)^2 becomes

(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2

Open bracket

\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})

\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}

Add Fraction

\frac{1 + 2sin^2x}{cos^2x} ------------------------ This is another equivalence

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In trigonometry

sin^2x + cos^2x= 1

Make sin^2x the subject of formula

sin^2x= 1  - cos^2x

................................................................................................................................

Substitute the expressions for 1  - cos^2x for sin^2x

\frac{1 + 2(1  - cos^2x)}{cos^2x}

Open bracket

\frac{1 + 2  - 2cos^2x}{cos^2x}

\frac{3  - 2cos^2x}{cos^2x} ---------------------- This is another equivalence

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5.) Find the perimeter and area of a triangle with a base of 11 cm, height of 13.4 cm, and sides of 15
adelina 88 [10]

Perimeter is the sum of the 3 sides:

11 + 15 + 14 = 40 cm.

Area is 1/2 x height x base:

1/2 x 13.4 x 11 = 73.7 square cm.

6 0
4 years ago
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