Answer:
A)1/18
B)1/6
C)13/18
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION BELOW,
The chess clubs of two schools consist of, respectively, 8 and 9 players. Four members from each club are randomly chosen to participate in a contest between the two schools. The chosen players from one team are then randomly paired with those from the other team, and each pairing plays a game of chess. Suppose that Rebecca and her sister Elise are on the chess clubs at different schools. What is the probability that (a) Rebecca and Elise will be paired? (b) Rebecca and Elise will be chosen to represent their schools but will not play each other? (c) either Rebecca or Elise will be chosen to represent her school?
CHECK THE ATTACHMENT'S FOR STEP BY STEP EXPLANATION
Answer:
he will have to work 17 hours.
Step-by-step explanation:
8.50×17=144.5
135+144.5=279.5
he will have $2.51 extra
Answer:
8
Step-by-step explanation:
When you subtract the 9-1=8
m₁ = mass hanged initially = 0.2 kg
x₁ = initial stretch in the spring = 8 cm = 0.08 m
k = spring constant of the spring
the weight of the mass hanged is balanced by the spring force by the spring hence
Spring force = weight of mass hanged
k x₁ = m₁ g
k (0.08) = (0.2) (9.8)
k = 24.5 N/m
m₂ = mass hanged later = 0.5 kg
x₂ = final stretch in the spring = ?
k = spring constant of the spring = 24.5 N/m
the weight of the mass hanged is balanced by the spring force by the spring hence
Spring force = weight of mass hanged
k x₂ = m₂ g
(24.5) x₂ = (0.5) (9.8)
x₂ = 0.2 m = 20 cm