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vitfil [10]
2 years ago
14

100 Points!!!! Please HELP!!!

Mathematics
1 answer:
Degger [83]2 years ago
5 0

Answer:

We can use the <u>tan trig ratio</u> to calculate the steepness of each run.

The side <em>opposite</em> the angle is the <em>vertical </em>distance of each path.

The side <em>adjacent </em>to the angle is the <em>horizontal </em>distance of each path.

(see attached diagram)

<u>Tan trig ratios</u>

\sf \tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

<u>Little Thunder</u>

\implies \sf \tan(\theta)=\dfrac{2}{7}

\implies \sf \theta=\tan^{-1}\left(\dfrac{2}{7}\right)

\implies \sf \theta=16^{\circ} \: (nearest\:degree)

Rating = EASY (green circle)

<u>Dodge Ridge</u>

\implies \sf \tan(\theta)=\dfrac{4}{6}=\dfrac{2}{3}

\implies \sf \theta=\tan^{-1}\left(\dfrac{2}{3}\right)

\implies \sf \theta=34^{\circ} \: (nearest\:degree)

Rating = MODERATE (blue square)

<u>Wild Side</u>

\implies \sf \tan(\theta)=\dfrac{4}{4}=1

\implies \sf \theta=\tan^{-1}(1)

\implies \sf \theta=45^{\circ}

Rating = DIFFICULT (black diamond)

<u>Pacific Crest</u>

\implies \sf \tan(\theta)=\dfrac{4}{8}=\dfrac{1}{2}

\implies \sf \theta=\tan^{-1}\left(\dfrac{1}{2}\right)

\implies \sf \theta=27^{\circ} \: (nearest\:degree)

Rating = EASY (green circle)

<u>Thunderbolt</u>

\implies \sf \tan(\theta)=\dfrac{6}{2}=3

\implies \sf \theta=\tan^{-1}(3)

\implies \sf \theta=72^{\circ} \: (nearest\:degree)

Rating = DIFFICULT (black diamond)

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<em />

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