The store has 28 notebooks in packs of 4. Three packs of notebooks are sold. How many packs of notebooks are left?

The vertices of ΔGHI are G (2, 4), H (4, 8), and I (8, 4). The vertices of ΔJKL are J (1, 1), K (2, 3), and L (4, 1). Which conc

Klio2033 [76]

Answer:

They are similar by the definition of similarity in terms of a dilation.

Step-by-step explanation:

The first step is finding the sides of each triangle.

In triangle GHI, we have that:

GH = sqrt((4-2)^2 + (8-4)^2) = 4.4721

HI = sqrt((8-4)^2 + (4-8)^2) = 5.6569

IG = sqrt((2-8)^2 + (4-4)^2) = 6

Now, for the triangle JKL, we have:

JK = sqrt((2-1)^2 + (3-1)^2) = 2.2361

KL = sqrt((4-2)^2 + (1-3)^2) = 2.8284

LJ = sqrt((1-4)^2 + (1-1)^2) = 3

The triangles are not congruent, because the sides are different

They are similar, because their sides have a proportion (sides of GHI are 2 times the sides of JKL). If they are similar, they have the same angles.

The ratio of their corresponding sides is 1:2, not 1:3

The ratio of their corresponding angles is 1:1, not 1:3

3 0

3 years ago

It’s not 3 but still need help with it

Leto [7]

Answer:

13

Step-by-step explanation:

5-(-8)=13

6 0

2 years ago

Read 2 more answers

PLEASE HELP I HAVE 2 MORE THEN IM DONE OR TONIGHT (then i start again tmr ;( )

ryzh [129]

Answer:

1. 9

2. 32

3.

4. 69

7 0

2 years ago

Read 2 more answers

PLEASE HELP ME!!!!!!!!!!!!!!!!!!

lilavasa [31]

Answer:

a) 4 - $vt - d = \frac{1}{2} at^{2}$

b) 1 - $2(vt - d) = at^{2}$

c) 6 - $\frac{2(vt - d)}{t^{2}} = a$

Step-by-step explanation:

It simply asks the steps to go from the original displacement formula to isolate a (the acceleration). It's just a matter of moving items around.

We start with:

$d = vt - \frac{1}{2} at^{2}$

We then move the vt part on the left side, then multiply each side by -1 (to get rid of the negative on the at side and to match answer choice #4):

$vt - d = \frac{1}{2} at^{2}$

Then we multiply each side by 2 to get rid of the 1/2, answer #1:

$2(vt - d) = at^{2}$

Finally, we divide each side by t^2 to isolate a (answer #6):

$\frac{2(vt - d)}{t^{2}} = a$

4 0

3 years ago

Which of the following is an equivalent equation obtained by completing the square of the expression below? x^2+6x−8=0 A (x+3)^2

valentina_108 [34]

Answer:

Solving the equation $x^2+6x-8=0$ by completing the square method we get $\mathbf{(x+3)^2=17}$

Option B is correct option.

Step-by-step explanation:

We need to solve the equation $x^2+6x-8=0$ by completing the square method.

For completing the square method: we need to follow: $a^2+2ab+b^2=(a+b)^2$

We are given:

$x^2+6x-8=0$

Solving by completing the square

$x^2+2(x)(?)+(?)^2-8=0$

We need to find ? in our case ? is 3 because 2*3= 6 and our middle term is 6x i,e 2(x)(3)=6x.

So, adding and subtracting (3)^2

$x^2+2(x)(3)+(3)^2-8-(3)^2=0\\(x+3)^2-8-9=0\\(x+3)^2-17=0\\(x+3)^2=17$

So, solving the equation $x^2+6x-8=0$ by completing the square method we get $\mathbf{(x+3)^2=17}$

Option B is correct option.

7 0

3 years ago