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morpeh [17]
3 years ago
11

Find the distance of segment RS with endpoints R(4.4) and S(-1,-1)

Mathematics
1 answer:
fomenos3 years ago
4 0

Step-by-step explanation:

RS=S-R

=(-1,-1)-(4,4)

=(-1-4,-1-4)

=(-5,-5)

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You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Makovka662 [10]

Answer:

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

To determine:

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

To determine:

Total amount = A = ?

so using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

3 0
3 years ago
What is the perimeter of the rectangle? Write your answer in scientific notation
marissa [1.9K]
The formula is 2(l+w) 
6 0
3 years ago
3. What is the slope of the line that contains the
dlinn [17]

Answer:

I think the answer would be -1/2 or D.

Step-by-step explanation:

Use this formula for calculating slope : y2-y1 / x2 - x1                                                            

1. label the pairs, 1 and 2

(-6, 1)  - ( x1, y1 )          or        (4,-4) - (x1, y1)

(4,-4) - ( x2, y2)                      (-6,1) - (x2, y2)  

(the order does not matter)

2. Than plug in your numbers

y2-y1 / x2 -x1                 y2-y1 / x2 -x1

-4 - 1 / 4 - (-6)        or        1 - (-4) / -6 - 4

= -5/10 or -1/2               = - 5/-10 or -1/2

im only in eight grade so i did my best explaining , and this hope it helps :)

7 0
3 years ago
4. A loan made on March 12 is due September 10 of the following year. Find the exact time for the loan in a non-leap year and a
saul85 [17]

Answer:

182 days

Step-by-step explanation:

Given:

Date on which loan is made = March 12

Due date of the loan = September 10

Now,

The months in between March and September and the number of days in the particular months are

Month                          Number of days

April                               30

May                                31

June                               30

July                                 31

August                            31

------------------------------------------

Total number of days =  153

also,

Number of days left in March after 12 are (31 - 12 ) = 19 days

and,

Number of days in September before the due date = 10 days

Hence, the total time for loan = 19 + 153 + 10 = 182 days

since the included months does not have the month of February. Therefore,

the time for both leap year and non-leap year will remain same.

7 0
3 years ago
Area of a circular ring: A = 4<img src="https://tex.z-dn.net/?f=%20%5Cpi%20" id="TexFormula1" title=" \pi " alt=" \pi " align="a
OleMash [197]
1a)      A = 4πpw
      /4πw = /4πw
  A / 4πw = p

1b) A = 4πpw
     22 = 4πp(2)
       p = 11/4π (≈0.87)

2a)        P = 2πr + 2x
      P - 2x = 2πr
        /2π      /2π
 P-2x / 2π = r

2b)    P = 2πr + 2x
      440 = 2πr + 2(110)
          r = 110/π (≈35.014)
      

      
8 0
3 years ago
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