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2 years ago

6

Find a quadratic polynomial each with the given number as the sum and product of its zeros respectively

2 answers:

Pavlova-9 [17]2 years ago

8 0

Answer:

The answer is 4x² – x – 4 = 0

Step-by-step explanation:

<h2>1st Method </h2><h3><u>Given</u>;</h3>

Sum of zeroes = α + β = (-b)/a = 1/4
Product of zeros = αβ = c/a = 1

Where,

a = 4
b = 1
c = 4

So, one quadratic polynomial satisfying is given condition is 4x² – x – 4 = 0

<h2>2nd Method</h2>

Sum of zeroes = 1/4

Product of zeros = 1

Remember this formula

x² – (α + β)x + αβ

x² – 1/4x + 1

4x² – x – 4 = 0

Thus, The quadratic polynomial is

4x² – x – 4 = 0.

NARA [144]2 years ago

5 0

Step-by-step explanation:

sum of zeroes = 1/4

product of its zeros = 1

so,

4x^2- x - 4

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Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

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Substituting x =0.2 and h= 0.2

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Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

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Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

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$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

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$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

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