Question

cylindrical vase holds 8,038.4 cubic centimeters of water. The height of the vase is 40 centimeters. What is the length of the radius to the nearest whole centimeter? Use 3.14 for π.

Answer 1

The radius of the cylindrical vase is 8 centimeters, if the cylindrical vase holds 8,038.4 cubic centimeters of water and the height of the vase is 40 centimeters.

Step-by-step explanation:

The given is,

                 Volume of cylindrical vase = 8038.4 cubic centimeters

                 Height of the cylindrical vase = 40 centimeters

Step:1

                Formula for volume of cylindrical vase,

                                     $Volume, V=\pi r^{2} h$......................(1)

               Where, r - Radius of cylindrical vase

                           h - Height of cylindrical vase  

                From the given,

                                      V = 8038.4 cubic centimeters

                                      h = 40  centimeters  

                Equation (1) becomes,

                             8038.4 $= \pi r^{2} 40$

                                          $=(3.14)(40)r^{2}$                               (∵ $\pi$ = 3.14 )

                               $8038.4 = 125.6 r^{2}$

                                      $r^{2} = \frac{8038.4}{125.6}$            

                                       $r =\sqrt{64}$

                                       r = 8 centimeters

Result:

           The radius of the cylindrical vase is 8 centimeters, if the cylindrical vase holds 8,038.4 cubic centimeters of water and the height of the vase is 40 centimeters.