Help with 3 and show all work

Mathematics

2 answers:

masya89 [10]3 years ago

6 0

X<=50.

< is less than
> is greater than

Without him paying the extra fee is <=50
x is pounds.
Now, you have x<=50.

Hope this helped☺☺

Over [174]3 years ago

3 0

Hi there!

The answer should be x<=50, or x is less than or equal to 50.

Your previous answer was almost correct, but the inequality actually has a less than or equal to sign since Michael could still be at exactly 50 pounds without having to pay extra. The charge only applies when the weight is more than 50 pounds.

Hope this helps!

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Jade wants to buy a $200,000 term life insurance policy. She is 34 years old. Using the premium table, what is her annual premiu

AnnZ [28]

Premium rates are usually for premium per fixed face value. Jade's annual premium for a 10 year policy is given by Option b: $1,202

<h3>How to calculate the total annual premium for $x ?</h3>

If its given that the annual premium is $p per $y face value, then we can calculate the annual premium for $1 face value and then use it to calculate annual premium for $x.

Using proportions, we get:

$\rm \$y \: face \: value : \$p \: annual \: premiun\\\\\rm \$1 \: face \: value : \$\dfrac{p}{y} \: annual \: premiun\\\\\rm \$x\:face\: value : \$\dfrac{p \times x}{y} \: annual \: premiun\\$

For given case, from the tables, we see that for age 34, and 10 year life insurance for female gender , there is annual premium of 6.01 per $1000 face value.
Thus, we have p = 6.01, y = 1000

Since Jade wants to buy Life insurance for $200,000, thus, x = $200,000

Putting it in the above derived formula, we get:

$\rm \$x\:face\: value : \$\dfrac{p \times x}{y} \: annual \: premium\\\\\rm \$200000\:face\: value : \$\dfrac{6.01 \times 200000}{1000} \: annual \: premium\\ = \$1202 \: annual \: premiun$