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4 years ago

Given : circle x with radius r and circle y with radius s

Mathematics

1 answer:

tigry1 [53]4 years ago

5 0

Answer:

we need to know the variables

Step-by-step explanation:

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The length of a rectangle is twice it’s width. The perimeter of the rectangle is 1/6 feet.

DiKsa [7]

Answer:

The width is 1/36 feet and the length is 1/18 feet.

The area is 1/12 feet.

Step-by-step explanation:

If the width is x, then the length is 2x. This means:

(2)x + (2)2x = 1/6 | Simplify

2x + 4x = 1/6

6x = 1/6 | Now we divide both sides by 6

x = 1/36 feet

We have found the width, and we know that the length is two times this, so the length is 1/18 feet. We can check by adding these:

1/36 + 1/36 + 1/18 + 1/18 = 1/6, which is the perimeter.

The area is just length times width, so the area is 1/36 * 1/18 = 1/12.

4 0

3 years ago

PLZ HELP NOW IM FAILING THIS CLASS (work not needed... just answers)

Tomtit [17]

Answer:

1.D

2.B

Step-by-step explanation:

question 1

-2(2)²+1/3(2)

-7/6

question 2

(-4x-2)(2x)

-8x²-4x

4 0

3 years ago

If p is the hypothesis of a conditional statement and q is the conclusion, which is represented by ~p → ~q?

AfilCa [17]

Conditional statement is a statement with a hypotesis and a conclusion:

If $\text{ \underline{ hypothesis } } p$ , then $\text{ \underline { conclusion } } q$ or mathematically $p\rightarrow q$ .

Converse statement of $p\rightarrow q$ is statement $q\rightarrow p$ .

If you negate (that means stick a "not" in front of) both the hypothesis and conclusion, you get the inverse: $\neg p\rightarrow \neg q$ .

Finally, if you negate everything and flip p and q (taking the inverse of the converse) then you get the contrapositive: $\neg q\rightarrow \neg p$ .

Then,

Answer: the correct choice is D (the inverse of the original conditional statement).

8 0

4 years ago

Read 2 more answers

Multiply. 4 × 16.7....

DaniilM [7]

Answer:

66.8

Step-by-step explanation:

Try only multiplying 16 and 4, then 0.7 and 4, then add them all up.

4 0

3 years ago

Sanya has a piece of land which is in the shape of a rhombus. She wants her one daughter and one son to work on the land and pro

Neporo4naja [7]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ Sanya has a piece of land which is in the shape of a rhombus.

★ She wants her one daughter and one son to work on the land and produce different crops, for which she divides the land in two equal parts.

★ Perimeter of land = 400 m.

★ One of the diagonal = 160 m.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Area each of them [son and daughter] will get.

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

Let, ABCD be the rhombus shaped field and each side of the field be $x$

[ All sides of the rhombus are equal, therefore we will let the each side of the field be $x$ ]

Now,

• Perimeter = 400m

$\longrightarrow \tt AB+BC+CD+AD=400m$

$\longrightarrow \tt x + x + x + x=400$

$\longrightarrow \tt 4x=400$

$\longrightarrow \tt \: x = \dfrac{400}{4}$

$\longrightarrow \tt x= \red{100m}$

$\therefore$ Each side of the field = 100m.

Now, we have to find the area each [son and daughter] will get.

So, For $\triangle$ ABD,

Here,

• a = 100 [AB]

• b = 100 [AD]

• c = 160 [BD]

$\therefore \tt Simi \: perimeter \: [S] = \boxed{ \sf \dfrac{a + b + c}{2} }$

$\longrightarrow \tt S = \dfrac{100 + 100 + 160}{2}$

$\longrightarrow \tt S = \cancel{ \dfrac{360}{2}}$

$\longrightarrow \tt S = 180m$

Using herons formula,

$\star \tt Area \: of \: \triangle = \boxed{\bf{{ \sqrt{s(s - a)(s - b)(s - c) } }}} \star$

where

• s is the simi perimeter = 180m

• a, b and c are sides of the triangle which are 100m, 100m and 160m respectively.

Putting the values,

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(180 - 100)(180 - 100)(180 - 160) }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(80)(80)(20) }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180 \times 80 \times 80 \times 20 }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{9 \times 20 \times 20 \times 80 \times 80}$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{ {3}^{2} \times {20}^{2} \times {80}^{2} }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = 3 \times 20 \times 80$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \red{ 4800 \: {m}^{2} }$

Thus, area of $\triangle$ ABD = 4800 m²

As both the triangles have same sides

So,

Area of $\triangle$ BCD = 4800 m²

Therefore, area each of them [son and daughter] will get = 4800 m²

${\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}$

★ Figure in attachment.

${\underline{\rule{290pt}{2pt}}}$

7 0

2 years ago

Read 2 more answers