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3 years ago

PLZ HELP NOW IM FAILING THIS CLASS (work not needed... just answers)

Mathematics

1 answer:

Tomtit [17]3 years ago

4 0

Answer:

1.D

2.B

Step-by-step explanation:

question 1

-2(2)²+1/3(2)

-7/6

question 2

(-4x-2)(2x)

-8x²-4x

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36 x p = 5p x 7.5 solve for p

USPshnik [31]

Answer:

Step-by-step explanation:

Let's solve your equation step-by-step.

36p=5p(7.5)

Step 1: Simplify both sides of the equation.

36p=37.5p

Step 2: Subtract 37.5p from both sides.

36p−37.5p=37.5p−37.5p

−1.5p=0

Step 3: Divide both sides by -1.5.

−1.5p

−1.5

p=0

8 0

3 years ago

Kenneth is inviting people to his parents' anniversary party and wants to stay at or below his budget of $6,000 for the food. Th

ohaa [14]

X= the number of adults
y=the number of children

Knenneth can´t afford more than $6000.

Therefore, the ineguality will be:
40x+15y≤6000

Answer: 40x+15y≤6000

7 0

3 years ago

Read 2 more answers

What is the solution to –2|2.2x – 3.3| = –6.6? x = –3 x = 3 x = –3 or x = 0 x = 0 or x = 3

Nonamiya [84]

x = 3

-2 | 2.2(3) -3.3 | = -6.6

-2 | 6.6 - 3.3 | = -6.6

-2 | 3.3 | = -6.6

-2 * 3.3 = -6.6

-6.6 = -6.6

6 0

3 years ago

Read 2 more answers

Is 29.9 a rational, integer, whole number or all of the above?

coldgirl [10]

Answer:

It is in integer

Step-by-step explanation:

An integer is any number positive or negative. A whole number would not have a decimal and if it were a rational number it could be written as a ratio.

5 0

3 years ago

g Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min, and its coarseness is such that it forms a pile in the sh

Maslowich

Answer:

0.3537 feet per minute.

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

$\dfrac{dV}{dt}=10$ ft^3/min$

$\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h$

If the Base Diameter = Height of the Cone

The radius of the Cone = h/2

Therefore,

$\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}$

$\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}$

Therefore: $\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=10$

We want to determine how fast is the height of the pile is increasing when the pile is 6 feet high.

$When h=6$ feet$\\\dfrac{3\pi *6^2}{12}\dfrac{dh}{dt}=10\\9\pi \dfrac{dh}{dt}=10\\ \dfrac{dh}{dt}= \dfrac{10}{9\pi}\\ \dfrac{dh}{dt}=0.3537$ feet per minute$

When the pile is 6 feet high, the height of the pile is increasing at a rate of 0.3537 feet per minute.

7 0

4 years ago