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Aleksandr-060686 [28]
3 years ago
14

Which answer describes the type of sequence? 1, 3, 5, 7, ......arithmetic, geometric, or neither arithmetic nor geometric?

Mathematics
2 answers:
Gnoma [55]3 years ago
6 0
Arithmetic; the difference is constant equal 2
Korolek [52]3 years ago
6 0
Arithmetic sequence, a(n+1) = 2a(n) - 1
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The formula for the area of a trapezoid is A = 1 2 h ( b 1 + b 2 ) , A= 2 1 ​ h(b 1 ​ +b 2 ​ ), where h h is the height and b 1
Sergeeva-Olga [200]

Answer:

h =  2A / (b1 + b2)

Step-by-step explanation:

A = 1/2h (b1 + b2)

Divide both sides by 1/2 (b1 + b2)

h  =  A / 1/2 (b1 + b2)

h =  2A / (b1 + b2)

7 0
3 years ago
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What is the center of the circle and radius defined by the following equation?<br><br> x2+y2+4y=5
vovangra [49]

Answer:

Step-by-step explanation:

Alternate forms:

x^2 + y (y + 4) = 5

x^2 + y^2 + 4 y - 5 = 0

Solutions:

y = -sqrt(9 - x^2) - 2

y = sqrt(9 - x^2) - 2

Integer solutions:

x = ± 3, y = -2

x = 0, y = -5

x = 0, y = 1

Implicit derivatives:

(dx(y))/(dy) = -(2 + y)/x

(dy(x))/(dx) = -x/(2 + y)

7 0
3 years ago
Can you write to me explaining this please
Mnenie [13.5K]

Answer:

In addition, from the response shown, using a graphical calculator brings the following benefits:

1) You can write the system of linear equations as big as you want. This is: systems 3 * 3, 4 * 4, 5 * 5.

2) The response to systems of equations greater than 2 * 2 can be complicated when you graph the solution, therefore, the graphing calculator can be much more efficient in these cases.

3) You can write the linear equations in any way. Resolving by hand you should probably rewrite the system of equations to find the solution.

Step-by-step explanation:

7 0
3 years ago
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Identify how the graph is shifted from that of the parent function.
Semenov [28]

Answer:

4 units left

Step-by-step explanation:

3 0
4 years ago
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Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the
mestny [16]

Answer:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

Step-by-step explanation:

Given

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Required

Determine the equivalent expression

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Simplify the first fraction

\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Apply law of indices on the first fraction;

5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}

\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}

Apply law of indices:

5q^5w^4*4\left(q^6\right)^2 * w^{5}

Evaluate the bracket

5q^5w^4*4 * q^{12} * w^{5}

Collect Like Terms

5*4q^5* q^{12}*w^4  * w^{5}

20q^5* q^{12}*w^4  * w^{5}

20q^{5+12}*w^{4+5}

20q^{17}w^9

Hence:

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9

7 0
3 years ago
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