A rectangular strip of land has length of 1/4 mile and an area of 5/6 square mile

Can you answer the first question for me

loris [4]

All are true except d

5 0

3 years ago

If $25, 000 is invested into an account paying 4.5% per year, compounded quarterly, how much money can be withdrawn from the acc

pogonyaev

The money can be withdrawn from the account every two months for the next 6 years is $20, 625, 000

<h3>What is compound interest?</h3>

The formula for compound interest is given as;

$A = P ( 1 + \frac{r}{n} )^n^t$

P = principal interest = $25, 000

r = rate = 4. 5%

n = 2 months

t = 6 years

A = $25, 000 ( 1 + \frac{4. 5}{2} )^2 ^*^6$

A = $25, 000(1 + 0. 75)^1^2$

A = $25, 000( 825. 00)$

A = $20, 625, 000

Thus, the money can be withdrawn from the account every two months for the next 6 years is $20, 625, 000

Learn more about compound interest here:

brainly.com/question/2455673

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7 0

1 year ago

People's movements between places is called

pogonyaev

Answer:

The three answers I can think of are migration, immigration, and emigration.

Step-by-step explanation:

Hope this helps!

5 0

2 years ago

Read 2 more answers

He first three terms of a geometric sequence are as follows. 10 , 30 , 90 find the next two terms of this sequence.+

ankoles [38]

10*3=30
30*3=90
90*3=270
270*3=810

or

10*3^1=30
10*3^2=90
10*3^3=270
10*3^4=810

the next two terms of this sequence are 270 and 810.

4 0

3 years ago

Please solve these questions for me. i am having a difficult time understanding.

s2008m [1.1K]

Answer:

1) AD=BC(corresponding parts of congruent triangles)

2)The value of x and y are 65 ° and 77.5° respectively

Step-by-step explanation:

1)

Given : AD||BC

AC bisects BD

So, AE=EC and BE=ED

We need to prove AD = BC

In ΔAED and ΔBEC

AE=EC (Given)

$\angle AED = \angel BEC$ ( Vertically opposite angles)

BE=ED (Given)

So, ΔAED ≅ ΔBEC (By SAS)

So, AD=BC(corresponding parts of congruent triangles)

Hence Proved

2)

Refer the attached figure

$\angle ABC = 90^{\circ}$

In ΔDBC

BC=DC (Given)

So, $\angle CDB=\angle DBC$ (Opposite angles of equal sides are equal)

So, $\angle CDB=\angle DBC=x$

So, $\angle CDB+\angle DBC+\angle BCD = 180^{\circ}$ (Angle sum property)

x+x+50=180

2x+50=180

2x=130

x=65

So, $\angle CDB=\angle DBC=x = 65^{\circ}$

Now,

$\angle ABC = 90^{\circ}\\\angle ABC=\angle ABD+\angle DBC=\angle ABD+x=90$

So, $\angle ABD=90-x=90-65=25^{\circ}$

In ΔABD

AB = BD (Given)

So, $\angle BAD=\angle BDA$ (Opposite angles of equal sides are equal)

So, $\angle BAD=\angle BDA=y$

So, $\angle BAD+\angle BDA+\angle ABD = 180^{\circ}$ (Angle Sum property)

y+y+25=180

2y=180-25

2y=155

y=77.5

So, The value of x and y are 65 ° and 77.5° respectively

8 0

3 years ago