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3 years ago

What is the value for ƒ(x) =

Mathematics

1 answer:

tia_tia [17]3 years ago

5 0

Answer:

Step-by-step explanation:

Put x as 1/2 and evaluate.

3^(2(½) + 1)

3^(1+1)

3²

= 9

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For which value of x is the equation 6 = 12x true?

skad [1K]

Answer:

x = 0.5

Step-by-step explanation:

5 0

3 years ago

in triangle PQR the measure of angle R=90, QP=73, RQ=55, and PR=48. what is the value of the sine of angle P to the nearest Hund

alexandr402 [8]

Answer:

P ≈ 48.89°(nearest hundredth)

Step-by-step explanation:

The triangle PQR forms a right angle triangle since angle R is 90°. The triangle has an hypotenuse , adjacent and opposite side.

Using the SOHCAHTOA principle one can find the sine ratio of angle P. Let us designate where each side represent.

opposite side(QR) = 55

adjacent side(PR) = 48

hypotenuse(PQ) = 73

sin P = opposite/hypotenuse

sin P = 55/73

P = sin⁻¹ 55/73

P = sin⁻¹ 0.75342465753

P = 48.8879095605

P ≈ 48.89°(nearest hundredth)

5 0

3 years ago

What the answer to this it pre algebra Order operation

olga55 [171]

PEMDAS

parenthesis

exponents

multiplication

division

addition

subtraction

9-7-6/6

first 6/6=1

9-7-1

9-7=2

2-1=1

answer is 1

5 0

3 years ago

Semicircles

Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is $9.1\ cm^2$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

$A=b^2$

where

b is the length side of the square

we have

$b=4\ cm$

substitute

$A=4^2=16\ cm^2$

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

$A=\pi r^{2}$

The diameter of the circle is equal to the length side of the square

$r=\frac{b}{2}=\frac{4}{2}=2\ cm$ ---> radius is half the diameter

substitute

$A=\pi (2)^{2}$

$A=4\pi\ cm^2$

Therefore, the area of 2 "not-shaded" regions is:

$A=(16-4\pi) \ cm^2$

and the area of 4 "not-shaded" regions is:

$A=2(16-4\pi)=(32-8\pi)\ cm^2$

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

$A=16-(32-8\pi)=(8\pi-16)\ cm^2$

---> exact value

assume

$\pi =3.14$

substitute

$A=(8(3.14)-16)=9.1\ cm^2$

8 0

4 years ago

I need to figure this out for a quiz in APEX. I can get the rest if I understand how to do this one.

KIM [24]

The answer is b
(-1,3,5)

Hope this helps!

8 0

3 years ago