1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lesantik [10]
4 years ago
6

Find the Area of the combined rectangles. Please explain it to me

Mathematics
1 answer:
fenix001 [56]4 years ago
3 0
Well, first since i split this up into 3 shapes. Then I multiplied 4x8 which was 32 and since there were two,it would be another 32. Then I multiplied 12x4 which was 48. Then I added 32+32+48 which equaled 112 square feet.
You might be interested in
Solve the equation<br><br> 3/4x = 60
PolarNik [594]
Multiply both sides by 4/3
x= 60 * 4/3
x= 80
7 0
3 years ago
Read 2 more answers
Tanya is training a turtle for a race. For every 1/2 of an hour that the turtle is crawling, he can travel 3/20 of a mile. At wh
vazorg [7]

Answer:

\frac{6}{20} \ mile\ per\ hour

Step-by-step explanation:

Given:

For every 1/2 of an hour that the turtle is crawling, he can travel 3/20 of a mile

Question asked:

At what unit rate is the turtle crawling?

Solution:

As here<u> time taken is given</u> and the <u>distance traveled is also given </u>and hence we will apply speed and distance formula to find rate of crawling of turtle.

Time taken by turtle = \frac{1}{2} \ hour

Distance which can be traveled by turtle = \frac{3}{20} \ miles

Speed =\frac{Distance}{Time}

         =\frac{3}{20} \div\frac{1}{2} \\\\ =\frac{3}{20} \times\frac{2}{1} \\ \\ =\frac{6}{20}

Therefore, the rate at which the turtle is crawling is \frac{6}{20} \ mile\ per\ hour

4 0
3 years ago
Need lots of help LOTS OF POINTS
bezimeni [28]
I'm not 100% sure but my best guess would be a rectangle. ( do not give brainliest if wrong, i wanna make sure its right)

7 0
3 years ago
Read 2 more answers
PROMPT:
pentagon [3]
For this answer let's pick the Fish Pond.

QUESTION: <span>What do you know? 
We know that the total area of the rectangular patio is 24 square feet. The rectangular fish pond that we want to build should have the length that is twice the width. We also need a 1-foot border around the pond.

The total area of the patio is represented by </span>2 x^{2} +6x+4 where x is the width of the fish pond.

QUESTION: What do you want to find out? 
We can answer this question by examining what we have been given (we have answered this in the previous question). Since we only have one variable in the equation and this is the width of the fish pond, then this is the only thing that we need to find out. The length will just follow after the width is solved. (Basically, we are concerned with the dimensions of our project.)

QUESTION: What kind of answer do you expect? 
Since we are only expecting to solve for the dimensions, then we should expect two numbers which would represent the width and the length. Through the polynomial, we can get the width of our project, then the length would just be twice our answer for the width.

1. To set our polynomial equation equal to the total area of our patio, we just write the equation on the left side and the total area of the patio on the right. We recall the equation that we gave in the first question above as well as the patio's area.

2x^{2} +6x+4=24

2. For this item, we just simply negate the constant term on the right side by subtracting the same number to both sides. Since our constant term is 24, we subtract 24 from the polynomial as well as the term on the right side.

2x^{2} +6x+4-24=24-24
2x^{2} +6x-20=0

3. In this item we are only tasked to find the GCF of the trinomial and factor it out of the left side of the equation. The GCF just means the common number or variable in all terms. Upon examining, we can see that the only common factor of the terms is 2 (since all terms are divisible by 2), thus this will be the GCF and we will factor this one out.

2(x^{2} +3x-10)=0

4. To factor the polynomial completely, we just figure out the possible factors of the quadratic equation. You can do this by trying out all factors of -10 that will have a sum of 3 (since -10 is the constant and 3 is the coefficient of x). Upon examining you should end up with:

2(x+5)(x-2)=0 (Notice that 5 and -2 are factors of -10 and their sum is 3).

5. The rule stated on this item just means that we can equate each individual factor to zero (except for the constant term) to find out the possible values of x. That means that we can solve for x by using the equations x+5=0 and x-2=0.

x+5=0
x=-5

x-2=0
x=2

6. For this item, we just do simple substitutions to the equation 2x^{2} +6x-20=0 to verify whether the values we got in question 5 is really a solution to the equation. The values of x that we got are -5 and 2 so we substitute these one at a time.

2(-5)^{2} +6(-5)-20=0
50-30-20=0
0=0

2(2)^{2} +6(2)-20=0
8+12-20=0
0=0

Both values of x make the left side equal to zero therefore both are solutions to the equation.

7. We can tell the dimensions of the project by looking at the values that we got for x, since we assumed x to be the width of our project. The fact that we got two values for x won't be a problem since one of these values is negative. There is no negative measurement/width so we can just ignore this negative value (-5). Thus, the width for our project would be 2 and the length would be twice this value which is 4.

Width = 2 feet
Length = 4 feet

8. For this item, we just illustrate the dimensions of our project and add a 1-foot border (as we are told initially). You can see this illustration in the picture I attached below. 

Since we have an extra 1 foot in every side, that means we need to add 2 feet to both the width and the length. Therefore, our width now is 4 while our length is 6.

Multiplying these numbers to verify the area, we get 24 square feet which is exactly the area of the patio.

6 0
3 years ago
Read 2 more answers
Hadley has 3/6 of a box of white envelopes and 1/3 of a box of gray envelopes. When full, each box of envelopes has the same num
QveST [7]

Answer:

<u>The two statements that apply are A and B.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

White envelopes Hadley has = 3/6 of a box

Gray envelopes Hadley has = 1/3 of a box

When full, each box of envelopes has the same number of envelopes

Hadley said she has 4/9 of a box when she puts the white envelopes and gray envelopes together.

2. Which statements describe this situation? Select the two statements that apply.

Let's add 3/6 and 1/3

3/6 + 1/3 = 3/6 + 2/6 = 5/6

A. Hadley’s answer is incorrect, because 3/6 is equal to 1/2 , and 4/9 is less then 1/2 .   This is correct.

B. Hadley's answer is incorrect, because 3/6 plus 1/3 equals 5/6.   This is correct.

C. Hadley's answer is incorrect, because 3/6 plus 1/3 equals 2/6.  This is wrong

D. Hadley's answer is correct, because 3 and 1 is 4, and 6 and 3 is 9. This is wrong.

<u>The two statements that apply are A and B.</u>

3 0
3 years ago
Other questions:
  • Evaluate the expression.<br> 2* (3^6 * 3^-5)
    11·2 answers
  • Evaluate y = ex + 1 for the following values of x. Round to the nearest thousandth. x = −2, y ≈ x = 1, y ≈ x = 2, y ≈
    6·2 answers
  • How to solve the proportion 9/5=3/x
    14·1 answer
  • 99pts WILL GIVE BRAINLIEST Use the diagram and given information to answer the questions and prove the statement. Given: X Z 
 P
    11·1 answer
  • A car dealership sold 78 cars in April. The dealership wants to increase the number of cars sold by 30% in
    11·1 answer
  • At Pizza Pi, 16% of the pizzas made last week had extra cheese. If 4 pizzas had extra cheese, how many pizzas in all were made l
    9·1 answer
  • Help! I need to know the circumference of the circle and the area of the half circle! Use 3.14 for pi
    13·1 answer
  • Direction: Solve the given problems.
    15·1 answer
  • What is the volume of the prism??
    9·1 answer
  • HELP ASAP!!!!PLEASE
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!