Question

Please help me differentiate this

Answer 1

Hello,

$x=t^2===\ \textgreater \ dx=2tdt\\\\ y=t^3===\ \textgreater \ dy=3t^2dt\\\\ \dfrac{dy}{dx} = \dfrac{3}{2} t\\\\ P=(p^2;p^3)===\ \textgreater \ t=p\\\\ Equation\ of\ the\ tangent:\\ y-p^3= \frac{3}{2}p(x-p^2)\\ ===\ \textgreater \ 2y-3px+p^3=0$