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chubhunter [2.5K]
3 years ago
9

A farmer raises only ducks and pigs. There are 55 animals in all on his farm, and 146 legs.

Mathematics
1 answer:
nordsb [41]3 years ago
8 0

Answer:

Number of ducks = 37

Number of pigs = 18

Step-by-step explanation:

Let,

x be the number of ducks

y be the number of pigs

According to given statement;

x+y=55     Eqn 1

2x+4y=146     Eqn 2 (As ducks will have 2 legs and pigs will have 4)

Multiplying Eqn 1 by 2

2(x+y=55)

2x+2y=110    Eqn 3

Subtracting Eqn 3 from Eqn 2

(2x+4y)-(2x+2y)=146-110

2x+4y-2x-2y=36

2y=36

Dividing both sides by 2

\frac{2y}{2}=\frac{36}{2}\\y=18

Putting y=18 in Eqn 1

x+18=55

x = 55-18

x = 37

Hence,

Number of ducks = 37

Number of pigs = 18

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