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Arada [10]
3 years ago
14

What is the point slope form of a line that has a slope of 3 and passes through the point (-1,4)

Mathematics
1 answer:
lukranit [14]3 years ago
6 0

Answer:

y - 4 = 3(x- (-1)     --->      y-4 = 3(x+1)

Step-by-step explanation:

y - 4 = 3(x + 1)

y - 4 = 3x + 3

y = 3x + 7

then plug in (-1,4)

4 = 3(-1) + 7

4 = -3 + 7

4 = 4

Point slope form looks like:

y - y₁ = m(x - x₁)

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In order to find the answer, you have to divide each grade's total by the number of hours it took them to make that money, which will give you the amount each class makes per hour. 

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AlekseyPX

> and < with the lines under it mean that they can also be equal to the constant on the other side (greater/less than or equal to)

So x <= 3 can be anything less than 3 and 3.

*the = in this inequality is the equivalent of a line

Now vice versa.

x => 3 can be anything greater than 3 and 3.

Now for the dots.

The open dots in signs are (< and >).

Basically they start at that point they are on but don't include it.

So an open dot at 3 pointing to the left means that the value is greater than 3 but does not include 3.

The closed dots in signs are (<= and =>).

They start at the point and include it.

So a closed dot a 3 pointing to the left means that the value is greater than 3 and includes 3.

Arrows.

Arrows pointing to the left mean that the values are getting bigger.

Arrows pointing to the right mean that the values are getting smaller.

ie : An arrow pointing to the left with a starting point at 3 = 3 and anything bigger, such as 4.

ie : An arrow pointing to the right with a starting point at 3 = 3 and anything smaller, such as 2.

Solve for problems.

The main concept is isolate the variable.

This basically means make the variable be lonely ^^

Use +, -, *, and /

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First, we would subtract 2 from both sides.

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Then, we would divide each side by 6, leaving the x alone.

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And voila! x is anything greater than 1/6 but it does not include 1/6.

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