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anastassius [24]
3 years ago
13

What is the equation for the statement, 22 more than z is 71?

Mathematics
2 answers:
lilavasa [31]3 years ago
5 0
"22 more than" is just 
22+
"z" is
z
"is 71" is the same as
=71
put everything together to get
22+z=71
all you have to do to find z is subtract 22 from both sides to get:
z=49
Deffense [45]3 years ago
3 0
The equation should be 22+z=71.
⇒ (22-22)+z=71-22
⇒ z= 49

Hope this would help~
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In ΔSTU, the measure of ∠U=90°, TU = 3.7 feet, and ST = 5.2 feet. Find the measure of ∠S to the nearest tenth of a degree.
tekilochka [14]

Answer:

  45.4°

Step-by-step explanation:

The angle and side lengths in a right triangle are related by ...

  Sin = Opposite/Hypotenuse

  sin(S) = TU/TS = 3.7/5.2

Using the inverse sine function, we have ...

  ∠S = arcsin(3.7/52)

  ∠S ≈ 45.4°

8 0
3 years ago
#11 Find the slope of a line<br> that passes through the<br> points (-1, -3) and (-6,5)
Elden [556K]
Y2-y1/x2-x1
5-(-3)/(-6-(-1))
8/-5
-8/5 is the slope
3 0
3 years ago
This entire quiz is going to be the end of me.
Korolek [52]

Given points (-5,-1) and (5,9):
Let (x1,y1) = (-5,-1)
(x2,y2) = (5,9)

Use the following distance formula:

d = √[(x2 - x1)^2 + (y2 - y1)^2]

d = √[(5 — (-5))^2 + (9 — (-1))^2]

d = √[(5 + 5)^2 + (9 + 1)^2]

d = √[(10)^2 + (10)^2]

Add similar elements:

d = √[(10)^2 • 2]

The squared root of 10^2 is 10, so it goes outside the square root:

d = 10 √2

Therefore, the correct answer is Option 3:
d = 10 √2

Hope this helps :)
5 0
3 years ago
Write an equation perpendicular to the line 6x+12y=24 and passing through (4,0)
noname [10]
Y = 2x - 8 is perpendicular to 6x+12y=24 and passes through (4,0)
6 0
3 years ago
The number of students who attended FPM in 2015 was 1380. In 2016, 1405 students attended FPM. what was the percent of change in
Fittoniya [83]

The percent of change in student enrollment is 1.81 % increase

<em><u>Solution:</u></em>

Given that, The number of students who attended FPM in 2015 was 1380

In 2016, 1405 students attended FPM

To find: Percent change

<em><u>The percent change is given by formula:</u></em>

\text { percent change }=\frac{\text { final value - initial value}}{\text { initial value }} \times 100

If the result is positive, it is percent increase

If the result is negative, it is percent decrease

From given,

Initial value in 2015 = 1380

Final value in 2016 = 1405

<em><u>Substituting the values in formula, we get</u></em>

<em><u></u></em>\text { percent change }=\frac{1405-1380}{1380} \times 100\\\\\text { percent change }=\frac{25}{1380} \times 100\\\\\text { percent change }= 0.01811 \times 100\\\\\text { percent change }= 1.81<em><u></u></em>

Thus percent of change in student enrollment is 1.81 % increase

6 0
3 years ago
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