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GalinKa [24]
2 years ago
13

I need help i don’t understand

Mathematics
1 answer:
UNO [17]2 years ago
4 0

9514 1404 393

Answer:

  x = 12.5

Step-by-step explanation:

The value of x is part of the value of an angle in a triangle where the other angles are known. This suggests that the relevant theorem is the "angle sum theorem," which tells you <em>the sum of angles in a triangle is 180°</em>.

This gives you the equation ...

  60° +60° +(4x+10°) = 180° . . . . total of all angles is 180°

  4x +130° = 180° . . . . . . . . . . collect terms

  4x = 50° . . . . . . . . . . . . subtract 130° from both sides

  x = 12.5° . . . . . . . . . divide both sides by 4

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nikitadnepr [17]

Answer:

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Step-by-step explanation:

7 0
2 years ago
Solve -11 2/3 * (-4 1/5)
eduard

Answer:pts

Solve -11 2/3 * (-4 1/5)=49

Step-by-step explanation:

do whatever is in parentheses first

mark me brainest plz

6 0
3 years ago
Read 2 more answers
What is the solution to the following system of equations?
Alchen [17]

Answer:

it has infinitely many solutions

3 0
3 years ago
The group has a 6 foot long table and a plastic tablecloth for the sale. The tablecloths package states that the tablecloth is 1
Alexxandr [17]
Yes because There are 182.2 cm in 6 feet

6 0
3 years ago
Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).
lions [1.4K]

Check the picture below.  so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}

(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill

\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}

6 0
2 years ago
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