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8090 [49]
3 years ago
7

Anya found the slope of the line that passes through the points (–7, 4) and (2, –3). Her work is shown below. Let (x2, y2) be (–

7, 4) and (x1, y1) be (2, –3). m = = = The slope is . What error did she make? She simplified the denominator incorrectly. The denominator simplifies to –7. She labeled the points incorrectly. The point (–7, 4) should be (x1, y1). She used an incorrect formula. The formula should be the change in y-values with respect to the change in the x-values. She used an incorrect formula. The formula should be the sum of the x-values with respect to the sum of the y-values.
Mathematics
2 answers:
Flauer [41]3 years ago
7 0

Answer:

C

Step-by-step explanation:

Lapatulllka [165]3 years ago
3 0

Answer:

She used an incorrect formula. The formula should be the change in y-values with respect to the change in the x-values

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have

(x2,y2)=(-7,4)

(x1,y1)=(2,-3)

Substitute the values

m=\frac{4+3}{-7-2}

m=\frac{7}{-9}

m=-\frac{7}{9}

therefore

She used an incorrect formula. The formula should be the change in y-values with respect to the change in the x-values

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answer is 2x+y=±8

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8 0
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Galina-37 [17]

Answer: Order the data to find the minimum, maximum, and quartiles.

206, 374, 421, 469, 489, 505, 531, 573, 702.

Step-by-step explanation: I hoped this helped in some way or form.

6 0
3 years ago
A triangle has vertices at (1,10), (-5,2), and (7,2). What is its orthocenter. Show your work.
kondor19780726 [428]

Answer:

Question: What is the orthocenter of a triangle with the vertices (-1,2) (5,2) and (2,1)?

The coordinates of point A are (-1,2), point B are (5,2), and point C are (2,1).

The orthocent is the intersection of the three altitudes. An altitude goes from a vertex and is perpendicular to the line containing the opposite side.

In the coordinate plane the equations of the altitudes can be found and then a system of equations can be solved.

Altitude 1. From point C perpendicular to the line containing side AB.

Slope of line AB is 0 (horizontal line), a vertical line is perpendicular to a horizontal line. Thus, the equation of altitude 1 is  x=2 .

Altitude 2. From point B perpendicular to the line containing side AC.

Slope of line AC is  −13 , the slope of a line perpendicular to line AC is 3. The equation of altitude 2 is  y=3x−13  

Altitude 3. From point A perpendicular to the line containing side BC.

Slope of line BC is  13 , the slope of a line perpendicular to line BC is  −3 . The equation of altitude 3 is  y=−3x−1  

The orthocenter is the point where all three altitudes intersect.

x=2  

y=3x−13  

y=−3x−1  

Use substitution to solve the first two equations  y=3(2)−13=−7  

The orthocenter is the point  (2,−7)  

we did not need the third equation, but we can use it as a check, plug the coordinates into the third equation:

−7=−3(2)−1  

−7=−6−1  

−7=−7  it works.

3 0
3 years ago
Uta invests an amount into a compound interest investment account that pays 6% a year. After six years, she withdraws her
irina [24]

Answer:

$352.48

Step-by-step explanation:

500 = P(1+6/100)^6

500 = P(1.141851912)

P = 500 / 1.1418519112 = 352.48

6 0
4 years ago
Geometry, Triangle in a circle. Find X show work and explain please
nikklg [1K]

Answer: x=7

Step-by-step explanation:

By the Intersecting Secants Theorem, we know that:

(5)(x+5)=(6)(6+4)

Having this, we can find the value of "x" by solving for "x":

Applying Distributive property:

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Subtract 25 from both sides of the equation:

5x+25-25=60-25\\5x=35

And finally dviding both sides of the equation by 5, we get:

\frac{5x}{5}=\frac{35}{5}\\x=7

7 0
3 years ago
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