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choli [55]
3 years ago
13

Suzette went to the mall with her uncle Louie and ended up having to borrow some money to finish her holiday shopping. Suzette s

aw an egg-beater that she wanted to get for her sister. It cost $12.00 and she said to her uncle, “If you will lend me as much money as I currently have in my wallet, I will buy the beautiful beater for Betty.” He agreed and lent her the money. At another store she found a handsome slide rule for her brother, also for $12.00. She made the same deal with her uncle. “If you will lend me as much money as I currently have in my wallet, I will buy the rad rule for Robert.” Once again, he agreed. Finally, Suzette decided to splurge on a CD for herself, which also happened to cost $12.00. You guessed it. She made the same deal with her uncle. This time however, after completing the transaction, her wallet ended up empty. How much money did Suzette have at the beginning of her shopping spree?
Mathematics
1 answer:
sergejj [24]3 years ago
4 0

Answer: she had 6 dollars at the beginning of her spree

Step-by-step explanation:

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Use the discriminant to predict the nature of the solutions to the equation 4x-3x²=10. Then, solve the equation.
AleksandrR [38]

Answer:

Two imaginary solutions:

x₁= \frac{2}{3} -\frac{1}{3} i\sqrt{26}

x₂ = \frac{2}{3} +\frac{1}{3} i\sqrt{26}

Step-by-step explanation:

When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.

The discriminant gives us information on how the solutions of the equations will be.

  1. <u>If the discriminant is zero</u>, the equation will have only one solution and it will be real
  2. <u>If the discriminant is greater than zero</u>, then the equation will have two solutions and they both will be real.
  3. <u>If the discriminant is less than zero,</u> then the equation will have two imaginary solutions (in the complex numbers)

So now we will work with the equation given: 4x - 3x² = 10

First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0

So:

4x - 3x² = 10

-3x² + 4x - 10 = 0 will be our equation

with this information we have that a = -3 b = 4 c = -10

And we will find the discriminant: b^{2} -4ac = 4^{2} -4(-3)(-10) = 16-120=-104

Therefore our discriminant is less than zero and we know<u> that our equation will have two solutions in the complex numbers. </u>

To proceed to solve the equation we will use the general formula

x₁= (-b+√b²-4ac)/2a

so x₁ = \frac{-4+\sqrt{-104} }{2(-3)} \\\frac{-4+\sqrt{-104} }{-6}\\\frac{-4+2\sqrt{-26} }{-6} \\\frac{-4+2i\sqrt{26} }{-6} \\\frac{2}{3} -\frac{1}{3} i\sqrt{26}

The second solution x₂ = (-b-√b²-4ac)/2a

so x₂=\frac{-4-\sqrt{-104} }{2(-3)} \\\frac{-4-\sqrt{-104} }{-6}\\\frac{-4-2\sqrt{-26} }{-6} \\\frac{-4-2i\sqrt{26} }{-6} \\\frac{2}{3} +\frac{1}{3} i\sqrt{26}

These are our two solutions in the imaginary numbers.

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What is the length of AB?
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