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3 years ago

Somebody please help me help me on this it’s GEOMETRY it is URGENT please DO NOT waste my answers

Mathematics

1 answer:

Norma-Jean [14]3 years ago

8 0

Answer:

∠G ≅ ∠Q

Step-by-step explanation:

<u>Given</u>

ΔBIG ≅ ΔPQZ

<u>Answer choices:</u>

BI≅PQ - yes correct, corresponding
∠B ≅ ∠P - yes correct, corresponding

∠G ≅ ∠Q - no, incorrect, it should read ∠G ≅ ∠Z

ZP ≅ GB - yes correct, corresponding

So, incorrect choice is the third one

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sp2606 [1]

Answer:

9.1

Step-by-step explanation:

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2 years ago

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What are the potential solutions of log4x+log4(x+6)=2?

lions [1.4K]

The potential solutions of $log_4x+log_4(x+6)=2$ are 2 and -8.

<h3>Properties of Logarithms</h3>

From the properties of logarithms, you can rewrite logarithmic expressions.

The main properties are:

Product Rule for Logarithms - $log_{b}(a*c)=log_{b}a+log_{b}c$
Quotient Rule for Logarithms - $log_{b}(\frac{a}{c} )=log_{b}a-log_{b}c$
Power Rule for Logarithms - $log_{b}(a^c)=c*log_{b}a$

The exercise asks the potential solutions for $log_4x+log_4(x+6)=2$ . In this expression you can apply the Product Rule for Logarithms.

$log_4x+log_4(x+6)=2\\ \\ x*(x+6)=4^2\\ \\ x^2+6x=16\\ \\ x^2+6x-16=0$

Now you should solve the quadratic equation.

Δ= $b^2-4ac=36-4*1*(-16)=36+64=100$ . Thus, x will be $x_{1,\:2}=\frac{-6\pm \:\sqrt{100} }{2\cdot \:1}=\frac{-6\pm \:10}{2}$ . Then:

$x_1=\frac{-6+10}{2}=\frac{4}{2} =2\\ \\ \:x_2=\frac{-6-10}{2}=\frac{-16}{2} =-8$

The potential solutions are 2 and -8.

Read more about the properties of logarithms here:

brainly.com/question/14868849

4 0

1 year ago

Solve for x, show all of your work: -2x – 4 < 10

NNADVOKAT [17]

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3 years ago

My math teacher gave me this problem, what is p+7=-9

marshall27 [118]

P = -16

Subtract 7 from both sides to isolate the variable.

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2 years ago

Line A is represented by the following equation:

Vesnalui [34]

- for line B so the set of equations to have no solutions bc. x+y=2 and so y=2-x
so from x+y=4 will result y=4-x

so this is the right equation for line B so the set of equations has no solutions

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2 years ago

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