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3 years ago

What is the area of the kite?

Mathematics

2 answers:

Elena-2011 [213]3 years ago

6 0

the most reasonable answer would be c

Anastaziya [24]3 years ago

4 0

Answer:

Step-by-step explanation: 6*6=36×1/2=18

6*6=36×1/2=18

6*10=60×1/2=30

30+30+18+18

60+36=96

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What sum of money amounts to rupees 8700 in 3 years at the rate of 24 % per annum

Zina [86]

Given:

Amount = 8700

Time = 3 years

Rate of interest = 24% per annum

To find:

The principal values.

Solution:

Formula for amount:

$A=P\left(1+\dfrac{r}{100}\right)^t$

Where, A is amount, P is principal, r is the rate of interest and t is the number of years.

Putting $A=8700,r=24,t=3$ , we get

$8700=P\left(1+\dfrac{24}{100}\right)^{3}$

$8700=P\left(1+0.24\right)^{3}$

$8700=P\left(1.24\right)^{3}$

$8700=1.906624P$

Divide both sides by 1.906624.

$\dfrac{8700}{1.906624}=P$

$4563.0391729=P$

$P\approx 4563.04$

Therefore, the principal value is about 4563.04.

8 0

2 years ago

Hi!

suter [353]

Answer:

1 median=60.3

2 missing number=38

Step-by-step explanation:

1 45+55+76+y+88+54/6

316+y/6=63.6

316+x381.6

x=381.6-316=65.6

2M4 =63

60-62+92+x/4=63

214+x=252

x=252-214

=38

7 0

2 years ago

Read 2 more answers

Use proper probability notation. Identify function and label inputs when using technology.

zhannawk [14.2K]

Answer:

0.1349

Step-by-step explanation:

Given that:

Sample size, n = 500

20% of 500 ; 0.2 * 500 = 100

p = 0.18 ; n = 500 ; 1 - p = 0.82

P(x ≥ 100) ;

Using the binomial probability relation :

P(x =x) = nCx * p(x)^x * (1 - p)^(n - x

P(x ≥ 100) = 500C100 * 0.18^100 * 0.82^400

P(x ≥ 100) = 0.1349

5 0

3 years ago

Question:

aivan3 [116]

Answer:

part A) The scale factor of the sides (small to large) is 1/2

part B) Te ratio of the areas (small to large) is 1/4

part C) see the explanation

Step-by-step explanation:

Part A) Determine the scale factor of the sides (small to large).

we know that

The dilation is a non rigid transformation that produce similar figures

If two figures are similar, then the ratio of its corresponding sides is proportional

Let

z ----> the scale factor

$\frac{CB}{C'B'}=\frac{CD}{C'D'}=\frac{BD}{B'D'}$

The scale factor is equal to

$z=\frac{CB}{C'B'}$

substitute

$z=\frac{4}{8}$

simplify

$z=\frac{1}{2}$

Part B) What is the ratio of the areas (small to large)?

<em>Area of the small triangle</em>

$A=\frac{1}{2}(2)(4)=4\ units^2$

<em>Area of the large triangle</em>

$A=\frac{1}{2}(4)(8)=16\ units^2$

ratio of the areas (small to large)

$ratio=\frac{4}{16}=\frac{1}{4}$

Part C) Write a generalization about the ratio of the sides and the ratio of the areas of similar figures

In similar figures the ratio of its corresponding sides is proportional and this ratio is called the scale factor

In similar figures the ratio of its areas is equal to the scale factor squared

4 0

3 years ago

Anyone know??please????? And right answers

Brut [27]

Answer:

ACB

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers