Answer:
2006 sorry if I’m wrong I divided it by 2
Step-by-step explanation:
Answer:
Yes.
Step-by-step explanation:
If a graph G doesn't have a circuit, we must have that

where
is the number of edges of the graph and
the number of vertices. However, in this case it holds that

Answer:
+213 is the correct answer
Answer:
Let's simplify step-by-step.
(−a)(−4 − 5a) − 3a(2 + a)
Distribute:
= (−a)(−4) + (−a)(−5a) + −3a^2 + −6a
= 4a + 5a^2 + −3a^2 + −6a
Combine Like Terms:
= 4a+5a^2 + −3a^2+ −6a
= (5a2+ −3a^2) + (4a + −6a)
= 2a2 + −2a
Final Answer:
= 2a^2−2a!