An integer is three more than another integer. Twice the larger integer is two less

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

3 0

Answer:

The integers are 4 and 7 or -2 and 1.

Step-by-step explanation:

You can make a system of equations with the description of the two integers.

1. x = y + 3

2. 2x + 2 = y^2

The simplest and the fastest way to solve this system in this case is substitution. You can substitute x for y + 3 in the second equation.

1. x = y + 3

2. 2(y + 3) + 2 = y^2

Now simplify and solve the second one. For convenience, I will just disregard the first equation for now.

2y + 6 + 2 = y^2

y^2 - 2y - 8 = 0

You can factor this equation to solve for y.

(y - 4) (y + 2) = 0

y = 4, y = -2

Now we can substitute the value of y for x in the first equation.

x = 7, x = 1

You might be interested in

Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.

Amiraneli [1.4K]

The correct representations of the given inequality are

–6x + 15 < 10 – 5x

and

A number line with an open circle at 5 and a bold line that starts at 5 and is pointing to the right. The correct options are the third and fourth options

<h3>Solving inequality</h3>

From the question, we are to solve the inequality

The given inequality is

–3(2x – 5) < 5(2 – x)

First, clear the brackets

–6x + 15 < 10 – 5x

NOTE: This is one of the correct representations of the inequality

Collect like terms

-6x + 5x < 10 - 15

-x < -5

Divide both sides by -1 and flip the sign

x > 5

Representing this on a number line, we get a number line with an open circle at 5 and a bold line that starts at 5 and is pointing to the right.

Hence, the correct representations of the given inequality are

–6x + 15 < 10 – 5x

and

A number line with an open circle at 5 and a bold line that starts at 5 and is pointing to the right. The correct options are the third and fourth options

Learn more on Inequalities here: brainly.com/question/246993

#SPJ1