1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mrac [35]
2 years ago
15

Escribe una ecuación para una linea que pase por los puntos (3,5) y (6,3). Responder con trabajo de apoyo​

Mathematics
1 answer:
Blababa [14]2 years ago
8 0

Answer:

y = -\frac{2}{3}x + 7

Step-by-step explanation:

Ambos puntos (3, 5) y (6, 3) están en esta línea.

You might be interested in
If f(x) = 5x − 1 and g(x) = 2x2 + 1, what is the value of (f × g)(-3)?
Softa [21]

f(x) = 5x − 1 and g(x) = 2x^2 + 1

(f × g)(x) =  (5x − 1)(2x^2 + 1)

(f × g)(x) = 10x^3 - 2x^2 + 5x - 1

Substitute x = - 3

(f × g)(-3) = 10(-3)^3 - 2(-3)^2 + 5(-3) - 1

(f × g)(-3) = 10(-27) - 2(9) -15 - 1

(f × g)(-3) =-270 - 18 - 16

(f × g)(-3) = -236

Answer

- 236

6 0
3 years ago
What's the factory of 10
sergey [27]

Answer:

1,2,5,10

Step-by-step explanation:

Do you mean factors? If so, these are the factors of ten.

3 0
2 years ago
Read 2 more answers
Anyone know how to do this with a explanation ?
storchak [24]

Answer:

30 degrees

Step-by-step explanation:

Since we know that all triangles equal 180 degrees, we can add the 2 given angles and subtract that from 180 to find the remaining angle.

90+60=150

180-150=30 degrees

8 0
3 years ago
What is the equation for this table? 30 points!!!!
Marat540 [252]
That was made up?cz I tried to solve it and I kept getting different #s
5 0
3 years ago
Find the area of the shaded region.
kolbaska11 [484]

Answer:

\boxed{ \tt\longrightarrow \: Area \:  Of  \: Shaded \:  region  \: =\boxed{ \tt 39  \: in²}}

Step-by-step explanation:

<u>Given:</u>

The Dimensions of Parallelogram are 12 in.(Base) and 7 in.(Height)

<em>And,</em>

The Dimensions of Rectangle are 9 in.(Length) and 5 in.(Breadth).

<u>To Find</u>:

The Area of Shaded region

<u>Solution:</u>

When the dimensions of parallelogram and the dimensions of rectangle are given, we need to find the Shaded region using this formula:

\boxed{\tt \longrightarrow Area  = (Parallelogram  - Rectangle)}

We know that the formula of Parallelogram is base*height[b×h] and the formula of rectangle is length*breadth[l*b] .

\tt\longrightarrow \: Area =B×h-l×b

Put their values accordingly:

\longrightarrow  \tt Area = (12 \times 7 - 9 \times 5)in {}^{2}

<u>Simplify it.</u>

<em>[</em><em>Follow BODMAS Rule strictly while </em><em>simplifying]</em>

\tt\longrightarrow \: Area = (84 - 45 ) in {}^{2}

\tt\longrightarrow \: Area = 39 \:  {in}^{2}

Hence, the Area of Shaded region would be 39 in² or 39 sq. in. .

\rule{225pt}{2pt}

I hope this helps!

8 0
2 years ago
Read 2 more answers
Other questions:
  • 1) 9 + 2h - 16<br> -7 + 2h
    8·2 answers
  • An artist sells 4 paintings for $20 each,4 sculptures for $60 each, and 4 photographs for $10 each at her art show. The artist s
    8·1 answer
  • The weight that a horizontal beam can support varies inversely as the length of the beam. Suppose that a 2-m beam can support 31
    11·2 answers
  • How to solve 3x+2y=-1, 6x+4y=0 by elimination
    8·1 answer
  • Wood floors are being refinished in an office. If the room is a square with 15 foot 6 inch sides, what will it cost to have the
    15·1 answer
  • Ace Bike Rentals rents bikes for $28 per day Renters can keep the bike for 8 hours Bart’s Bikes rents bikes for $30 per day Rent
    7·1 answer
  • The scale of a drawing is 1 in.:4ft. Find the drawing length that would be used to represent an actual length of 24ft.
    12·1 answer
  • What is the equation of a line that passes through 2,-3 with a slope of 2/3
    11·2 answers
  • Help!<br> Find the measurement indicated in the trapezoid.
    11·1 answer
  • Find the LCM of: 14a^4n^2 and 35a^3mn^2 https://brainly.com/question/25332219
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!