Given:
The equation is:

To find:
The solution for the given equation to the nearest hundredth.
Solution:
We have,

Divide both sides by 3.


Taking ln on both sides, we get

![[\because \ln e^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20e%5Ex%3Dx%5D)
Divide both sides by 2.4.

![[\because \ln (90)\approx 4.4998]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20%2890%29%5Capprox%204.4998%5D)

Round the value to the nearest hundredth (two decimal place)

Therefore, the value of K is 1.87.
First, find the LCD; that is 9.
2/3 = 6/9
6/9 – 2/9 = 4/9
There is 4/9 of the pizza left.
Answer:
D. $25,400
Step-by-step explanation:
Let x represent the score during December.
We have been given that during 1 months of a recent year, a certain charitable organization received an average (arithmetic mean) of $20,600 per month in donations.
The total score for 11 months would be
.
We can set our given information in an equation as:





Therefore, the organization received $25,400 in donations during December and option D is the correct choice.