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timurjin [86]
3 years ago
10

18. Given points A(1,5), B(-2,-1), C(1,1).and D(3,5). what type of lines are ABand CD?​

Mathematics
1 answer:
Lelechka [254]3 years ago
4 0

Answer:

The line segments are parallel.

Step-by-step explanation:

First, I never have graph paper when it is needed so I suggest Geogebra.com.

Now slope is found by rise over run so I took the points on the graph and counted where they intersected with any other points on the line. AB was 2/1 which means 2. I did the same for the other line segment and found 2/1 : 2. so both of the slopes are the same so you have parallel lines.

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Also called regrouping this is when adding numbers results in more than two digits and one digit is placed in the colum to the l
kotykmax [81]

Answer:

Carrying forward.

Step-by-step explanation:

  • When regrouping is done to add the numbers where results in a more than 2 digit and one digit is placed to left Colum is called as carrying forward. As regrouping refers to carrying the place values in order to perform operations like addition or subtraction.
6 0
3 years ago
Gianna is taking a multiple choice test with a total of 100 points available. Each question is worth exactly 5 points. What woul
tatiyna

Answer:

Her test score would be an 85 because 5x3=15 and then you would subtract 15 from 100 which would be 85

equation would be x=100-(5y)

8 0
3 years ago
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Sonya expected to get $60 for her birthday ,but she only got $40.What was the percentage decrease of the amount Sonya recieved?
kow [346]
Are you asking about the percent of change?if so the answer is 33.3%.
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3 years ago
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The number of withdrawals a bank processes in a day follows a random variable X. The number of deposits in a day is represented
Serhud [2]

Answer:

Check the explanation

Step-by-step explanation:

Number of transactions in a day is sum of number of withdrawals and number of deposits. So,

Number of transactions in a day, Z = X + Y

Moment Generating function of Z is,

T+1

Expected number of transactions in a day = E[Z]

= \frac{\mathrm{d} }{\mathrm{d} t}_{t=0}M_Z(t) = (r+1)\left ( \frac{p}{1-qe^t} \right )^{r} * \frac{-p}{(1-qe^t)^2} * (-qe^t)    for t = 0

= (r+1)\left ( \frac{p}{1-qe^0} \right )^{r} * \frac{-p}{(1-qe^0)^2} * (-qe^0)

= (r+1)\left ( \frac{p}{1-q} \right )^{r} * \frac{-p}{(1-q)^2} * (-q)

= (r+1)\left ( \frac{p}{p} \right )^{r} * \frac{-p}{(p)^2} * (-q)

= \frac{(r+1)q}{p}

4 0
3 years ago
Find the sum of: <br> (2×3 - 7×2+ 10× - 8) ÷ (× - 2) <br><br>with step by step explanation <br>​
jonny [76]

Answer:

-8±10x

Step-by-step explanation:

you will follow BODMAS

B=bracket

O= off

D=division

M=multiplication

A=addition

S=subtraction

2×3=6

7×2=14

[6-14±10x-8]÷[x-2]

14±8=22

6-22=-16

[-16±10x]÷[x-2]=-8±10x

4 0
2 years ago
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