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laiz [17]
3 years ago
6

An enzyme is subject to allosteric regulation . how would you design an inhibitor of the enzyme that was competitive? non-compet

itive? irreversible?
Biology
1 answer:
ollegr [7]3 years ago
8 0
Allosteric regulation or non-competitive is the same concept. Allosteric means, from the Greek, another place/other space.
So, starting by a non-competitive inhibitor, you could design an enzyme like a circle with two separate spots/recesses, symbolising connecting spots, one for the inhibitor and another one for the substrate. When the inhibitor is then placed into its position it changes the conformity of substrate's spot impeding it to connect.
For a competitive inhibitor, you could again design an enzyme like a circle but now only with a single binding spot where the inhibitor would connect so the substrate could not.
As for the irreversible inhibitor, you could design an enzyme as a circle again but it doesn't matter where you connect the inhibitor, whether on the substrate spot or not, as long as you make clear that there is a strong covalent bond between the enzyme and the inhibitor that doesn't allow the substrate to bind to the enzyme. You could represent this covalent bond by a simple trace connecting the enzyme to the inhibitor: -- .
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Complete question:

Imagine that a newly discovered, recessively inherited disease is expressed only in individuals with type O blood, although the disease and blood group are independently inherited.

A normal man with type A blood and a normal woman with type B blood have already had one child with the disease. The woman is now pregnant for a second time.

Assuming that both parents are heterozygous for the gene that causes the disease, what is the probability that the second child will also have the disease? Express your answer as a fraction using the slash symbol and no spaces (for example, 1/2).

Answer:

The probability that the second child will also have the disease is 1/16.

Explanation:

<u>Available data:</u>

  • Two genes independently inherited: one for blood type, the other for disease
  • Man with type A blood  x  Woman with type B blood
  • Both parents are heterozygous for the gene that causes the disease; Dd

If the man has A blood, and the woman has B blood, and they already have an affected child, this means that they must be heterozygous for blood type too.

Cross:  

Parentals)           AiDd         x      BiDd

Gametes)  AD  Ad  iD  id       BD  Bd  iD  id

Punnett square)      AD       Ad       iD       id

                     BD   ABDD  ABDd  BiDD BiDd

                     Bd   ABDd   ABdd   BiDd Bidd

                     iD    AiDD    AiDd    iiDD   iiDd

                     id    AiDd     Aidd     iiDd    iidd

F1) <u>Genotype</u>:

1/16 ABDD

2/16 ABDd

1/16 ABdd

1/16 AiDD

1/16 BiDD

2/16 AiDd

2/16 BiDd

1/16 Aidd

1/16 Bidd

1/16 iiDD

2/16 iiDd

1/16 iidd

<u>Phenotype:</u>

3/16 A/B normal

4/16 A normal

4/16 B normal

3/16 0 normal

1/16 0 affected by the disease.

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