First find the slope the slope of the line that passes through (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
given (-4,3) and (6,-2) the slope is (-2-3)/(6-(-4))=(-5)/(6+4)=-5/10=-1/2
so the equation of a line tat passes through the point (x1,y1) and has a slope of m is y-y1=m(x-x1) use (-4,3) and we found slope=-1/2 y-3=-1/2(x-(-4)) y-3=-1/2(x+4) if yo want slope intercept form y-3=-1/2x-2 y=-1/2x+1 if yo want standard form 1/2x+y=1 x+2y=2