Answer:
Z= 0.253
Z∝/2 = ± 1.96
Step-by-step explanation:
Formulate the null and alternative hypotheses as
H0 : u1= u2 against Ha : u1≠ u2 This is a two sided test
Here ∝= 0.005
For alpha by 2 for a two tailed test Z∝/2 = ± 1.96
Standard deviation = s= 15
n= 10
The test statistic used here is
Z = x- x`/ s/√n
Z= 2058- 2046 / 15 / √10
Z= 0.253
Since the calculated value of Z= 0.253 falls in the critical region we reject the null hypothesis.
There is evidence at the 0.05 level that the doors are too short and unusable.
Answer:
There is a 25.52% probability of observating 4 our fewer succesful recommendations.
Step-by-step explanation:
For each recommendation, there are only two possible outcomes. Either it was a success, or it was a failure. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem we have that:

If the claim is correct and the performance of recommendations is independent, what is the probability that you would have observed 4 or fewer successful:
This is

In which







There is a 25.52% probability of observating 4 our fewer succesful recommendations.
1/4 (6 + s)
One-fourth (1/4) of the sum (+) of: 6 and s (6 + s)
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Given the choices, the best fitting answer would be the first one. "2 loaves of bread and 4 batches of muffins". I figured this out by multiplying the amount of flour and sugar required for each loaf of bread and batch of muffins