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3 years ago

11

Give a counterexample for the statement all square roots are irrational numbers explain your reasoning

2 answers:

valina [46]3 years ago

8 0

Not all square roots are irrational. This can be proven by finding the perfect square roots. The sqrt. of 16, 25, and 26, for example, the answers are all rational numbers.

I hope this is what you are asking for; let me know if you need anythings else :)

konstantin123 [22]3 years ago

4 0

An irrational number is a number that has an everlasting decimal (9.34560292348857485...). (If the decimal repeats, it is not irrational. 9.476666666...)
This is false because the square root of an even number are not irrational.
The square root of 16 is 4. The square root of 144 is 12.

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The number of likes a social media post has gotten is modeled by the exponential

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Answer:

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Step-by-step explanation:

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3 years ago

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Wewaii [24]

Answer:

15 minutes

Step-by-step explanation:

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Her rate alone is 1/10 floor per minute.

His rate is the difference of these:

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It would take Jacob 15 minutes to do it alone.

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3 years ago

Place 3 numbers between 12 and 60 to make a sequence of 5 numbers with a common difference

Vilka [71]

The 3 numbers which should be placed between 12 and 60 are; 24, 36 and 48.

<h3>What three numbers should be placed between 12 and 60?</h3>

It follows from the task content that the first and last numbers are; 12 and 60 respectively.

Hence, since the difference between 12 and 60 is 48 and there are 4 transitions between the two numbers to have 5 total numbers,

It follows that the common difference is; 48/4 = 12 and the three numbers required are; 24,36 and 48.

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5 0

2 years ago

What is the standard form of the polynomial 4x+6y^3x-xy+xy^2

meriva

The required standard form is $6y^3x+xy^2-xy+4x$

<h3>Polynomial function</h3>

Given the polynomial function expressed as:

$4x+6y^3x-xy+xy^2$

We are to express this polynomial in standard form

To do that, we will write the degrees of the variables in descending order of magnitude as shown:

$4x+6y^3x-xy+xy^2\\6y^3x+xy^2-xy+4x$

Hence the required standard form is $6y^3x+xy^2-xy+4x$

Learn more on polynomial functions here: brainly.com/question/7693326

7 0

2 years ago

I WILL MARK BRAINLIST!!

Soloha48 [4]

Answer:

For $(2x^2 + 8x - 8)$ , the group is CLOSED as it a polynomial.

Step-by-step explanation:

Here, the given polynomials are:

$P(x)=(5x^2+2x-6)\\Q(x)=(3x^2-6x+2)$

Now, a group G is said to be <u>CLOSED UNDER SUBTRACTION</u> if,

a and b are he elements of G ⇒ (a-b) is ALSO AN ELEMENT of G

Now, here:

$R(x) = P(x) - Q(x) = (5x^2+2x-6) - (3x^2-6x+2) = (2x^2 + 8x - 8)$

or, $R(x) = (2x^2 + 8x - 8)$

Also, R(x) is a POLYNOMIAL.

So, R(x) is an Element of group G.

So, the set G of polynomials.

Hence, for the polynomial $(2x^2 + 8x - 8)$ , it will be a polynomial the group is CLOSED.

3 0

3 years ago

Read 2 more answers