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KatRina [158]
2 years ago
6

Tommy is a video game designer at a new start-up company. How much does he make per month?

Mathematics
2 answers:
Ostrovityanka [42]2 years ago
7 0
7,103 monthly is what he makes
IrinaVladis [17]2 years ago
3 0

Answer:

$ 7,103.33 per month

Step-by-step explanation:

85,240 ÷ 12 = 7,103.3333333333 or 7,103.33 or 7,103.3

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A cube has a length, width and height of 6 feet. What is the volume in cubic INCHES?
Inessa05 [86]

Answer:

Step-by-step explanation:

4 0
3 years ago
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Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t
Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1.f(x)=\frac{x^2+x-20}{x^2+4}

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345

3.h(x)=\frac{3x-5}{x^2-5x+7}

x^2-5x+7=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43

2.g(x)=\frac{x-17}{x^2+75}

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12

4.i(x)=\frac{x^2-9}{x-9}

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is  not continuous on the set of real numbers.

5.j(x)=\frac{4x^2-7x-65}{x^2+10}

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0

6.k(x)=\frac{x+1}{x^2+x+29}

x^2+x+29=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102

7.l(x)=\frac{5x-1}{x^2-9x+8}

x^2-9x+8=0

x^2-8x-x+8=0

x(x-8)-1(x-8)=0

(x-8)(x-1)=0

x=8,1

The function is not defined for x=8 and x=1

Hence, function l is not  defined for all real values.

8.m(x)=\frac{x^2+5x-24}{x^2+11}

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0
3 years ago
what is the answer for this question and can tell me how to do this problem too. 791 + 11 &gt; 959 − 13
kompoz [17]

Answer:

The question is false

Step-by-step explanation:

4 0
3 years ago
Which of the following are independent variables?
Lapatulllka [165]

Answer:

i think that it is oil

Step-by-step explanation:

because it does not change

4 0
3 years ago
Read 2 more answers
What is (9x 2/3) x 2/3
Montano1993 [528]

Answer:

4

Step-by-step explanation:

(9 x 2/3) x 2/3

9x 2 = 18

18/3 = 6

6 x 2 = 12

12/3 = 4

(9 x 2/3) x 2/3 = 4

6 0
2 years ago
Read 2 more answers
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