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3 years ago

A card is drawn from a standard deck of cards. Find the probability, given that the card is a non-face card.

Mathematics

1 answer:

Rashid [163]3 years ago

8 0

Answer:

6.75

Step-by-step explanation:

54 cards in a deck p(8) so do 54 divided by 8 which should equal 6.75

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In one game, the ratio of three-point baskets to three-point tries for one team was 3:8. If the team scored 27 points from three

nasty-shy [4]

Since we’ve been given a ratio, 3:8, we can convert that into a fraction and form an equation from it:

$\frac{3}{8}$ = $\frac{27/3}{?}$

The reason the numerator on the second fraction is 27/3 is because the team scored 27 points, not 27 baskets.

Simplify (Also replace the ? with an unknown variable):

$\frac{3}{8}$ = $\frac{9}{n}$

Cross multiply:

3*n = 9*8

Simplify:

3n = 72

Divide both sides by 3:

n = 24

The team had 33 three point tries, 9 successes, and 24 fails.

-T.B.

7 0

3 years ago

Why is 1/2 the same as 0.5

Basile [38]

Answer:

it’s because 0.50 is half of 100 and 1/2 is a reduced fraction of 50/100.

Step-by-step explanation:

5 0

2 years ago

Can someone help me with 1& 2 will mark brainiest

melamori03 [73]

Sin 45° = opposite side / hypotenuse

1/2 = 8/h
h = 16

2)6/12 = 1/2
1/2 = sin 45°

6√3/12 = √3/2
√3/2 = cos 30°

Sum of angles of triangle = 180°
The 3rd angle = 180 - (45 + 30) = 180 - 75 = 105°

Angles = 30° , 45° , 105°

7 0

3 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

3 years ago

Find the slope of the line that passes through (4, 10) and (1, 2).

givi [52]

The slope is about 2.6667, the angle is almost 70° and the distance is 8.5 ish maybe even a little less

8 0

3 years ago

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