The value of the function h(x + 1) is -x^2 - x + 1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(x + 1)
This means that t = x + 1
So, we substitute t = x + 1 in the equation h(t) =-t^2 + t + 1
h(x + 1) =-(x + 1)^2 + (x + 1) + 1
Evaluate the exponent
h(x + 1) =-(x^2 + 2x + 1) + x + 1 + 1
Expand the brackets
h(x + 1) = -x^2 - 2x - 1 + x + 1 + 1
Evaluate the like terms
h(x + 1) = -x^2 - x + 1
Hence, the value of the function h(x + 1) is -x^2 - x + 1
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(x + 1)
Answer:
x = 3
Step-by-step explanation:
y = 3 is the equation of a horizontal line parallel to the x- axis.
A line perpendicular to it must therefore be a vertical line parallel to the y- axis with equation
x = c
where c is the value of the x- coordinates the line passes through.
The line passes through (3, 5) with x- coordinate 3 , thus
x = 3 ← equation of perpendicular line
Answer: The correct answer is March and September
pls mark brainliest
Answer:
The answer would be 2.7. Am not very sure though
Step-by-step explanation:
So what you do is
for example the unkown number is x and the answer you get is y
12-x=y * -15=-140
-140/-15=9.33 (this is y the answer)
12-x=9.3
12-9.3=2.7
To check your answer
12-2.7=9.3
9.3 * -15=-139.5 if you round it then it would be -140
Let the number = 10x+y
x+y = 9
y-x = 1
(x+y)+(y-x) = 9+1
2y = 10
y = 10/2
<h3><u>y = 5</u></h3>
x+y = 9
9-y = x
x = 9 - 5
<h3><u>x = 4</u></h3>
<h2>So, your number is <u>45</u></h2>
... Hope this will help...