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AveGali [126]
4 years ago
10

Which expression is equivalent

Mathematics
1 answer:
NemiM [27]4 years ago
8 0
Answer:
6(3) - 4 + (3)^2

Explanation:
We will do this on two steps:
1- get g(x)-f(x)
2- substitute with x = 3

Step 1:
f(x) = 4-x^2
g(x) 6x
g(x) - f(x) = 6x - (4 - x^2)
               = 6x - 4 + x^2

Step 2:
Substitute with x = 3 as follows:
g(x) - f(x) at x = 3 is:
6(3) - 4 + (3)^2

Hope this helps :)

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20% of what number is 75?
nataly862011 [7]

Answer:

15

Step-by-step explanation:

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What is it written in simplest form
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3 years ago
Please find the least common denominator for 3/8 <br> 5/12
andriy [413]

Answer:

24

Step-by-step explanation:

Given two fractions \frac{3}{8} and \frac{5}{12}.

Factor the denominators of both fractions:

8=2\cdot 4=2\cdot 2\cdot 2\\ \\12=2\cdot 6=2\cdot 2\cdot 3

You can see that two digits 2 are the same in both denominators and there are two more factors: 2 in number 8 and 3 in number 12.

Thus, the least common denominator for  \frac{3}{8} and \frac{5}{12} is

2\cdot 2\cdot 2\cdot 3=24

7 0
4 years ago
It took John 3 minutes to drive 18 laps. How many laps per minute did he run?
Crank
He ran 6 laps per minute. 18/3=6
8 0
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Find all complex solutions of 7x^2-7x+3=0
Sedaia [141]

Answer:

The complex solutions are

x =  (\frac{7-\sqrt{35}  i }{42} , ) x =  \frac{7 + \sqrt{35} i }{42})

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equation  7 x² - 7 x +3=0

                     x =  (\frac{-b -\sqrt{b^{2}-4ac } }{2ac} ,  \frac{-b +\sqrt{b^{2}-4ac } }{2ac})

Given standard equation

                         a x² +b x +c =0

 a = 7 , b= -7 and c=3

<u><em>Step(ii):-</em></u>

<u><em></em></u>x =  (\frac{-(-7) -\sqrt{(-7)^{2}-4(7)(3) } }{2(7)(3)} ,  \frac{-(-7) +\sqrt{(-7)^{2}-4(7)(3) } }{2(7)(3)})<u><em></em></u>

<u><em></em></u>x =  (\frac{7-\sqrt{(49-84 } }{42} ,  \frac{7 +\sqrt{(49-84 } }{42})<u><em></em></u>

x =  (\frac{7-\sqrt{35i^{2} }  }{42} ,  \frac{7 + \sqrt{35i^{2} }  }{42})

x =  (\frac{7-\sqrt{35}  i }{42} ,  \frac{7 + \sqrt{35} i }{42})

<u><em></em></u>

8 0
3 years ago
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