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Oksi-84 [34.3K]
3 years ago
10

Aisha changed 1.45 + 2.38 to 1.5 + 2.4 in order to estimate the sum. What estimation method did she use? front-end clustering ro

unding to the nearest tenth rounding to the nearest hundredth
Mathematics
2 answers:
Rasek [7]3 years ago
9 0
The answer is c: rounding to the nearest tenth
Dmitry_Shevchenko [17]3 years ago
8 0
She rounded to the nearest tenth.

1.45 rounded to the nearest tenth would be 1.5 and 2.38 rounded to the nearest tenth would be 2.40 (or 2/4)

Hope this helped! :)

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You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard devia
Arturiano [62]

Answer:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (3)

n=(\frac{2.58(54.5)}{5})^2 =790.846 \approx 791

So the answer for this case would be n=791 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (2)

And on this case we have that ME =+5 and we are interested in order to find the value of n, if we solve n from equation (2) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (3)

n=(\frac{2.58(54.5)}{5})^2 =790.846 \approx 791

So the answer for this case would be n=791 rounded up to the nearest integer

4 0
3 years ago
13 points plus brainliest to the correct answer!
TEA [102]
The equation of a straight line is given by:

y = mx + c

where m is the slope and c is the y-intercept.

From the given graph, the y-intercept is 1.

The slope of a straight line is given by:

m= \frac{y_2-y_1}{x_2-x_1}

Where (x_1,y_1) and (x_2,y_2) are two points on the line.

From the graph, (0, 1) and (14, 8) are two points on the line, thus:

m= \frac{8-1}{14-0} = \frac{7}{14} = \frac{1}{2}

Therefore, the equation representing the graph is y= \frac{1}{2} x+1
8 0
3 years ago
Read 2 more answers
What is 805 ten equal to
Anna007 [38]
805 tens is equal to 8050 ones

7 0
3 years ago
If the Price Elasticity of Demand for a product is -.8, and the product currently sells for $100 per unit, how much will demand
egoroff_w [7]

Answer: Percentage change in quantity would decrease by 12.5%.

Step-by-step explanation:

Since we have given that

Price elasticity of demand = -0.8

Price of each unit = $100

After change, price of each unit becomes = $110

% change in quantity would be

\dfrac{New-old}{old}\times 100=\dfrac{110-100}{100}\times 100=10\%

As we know the relation between price, quantity and elasticity.

e_D=\dfrac{\text{\% change in quantity}}{\text{\%change in price}}\\\\-0.8=\dfrac{10\%}{x}\\\\x=\dfrac{10}{-0.8}\\\\x=-12.5\%

Hence, Percentage change in quantity would decrease by 12.5%.

8 0
3 years ago
The weekly salary of a store manager includes a $30 bonus plus the number of hours the manager works multiplied by the managers
just olya [345]

Answer:

Yes this is a linear function f(x) = ex+30

e = hourly rate

x=hours

f(x) = total earnings

6 0
3 years ago
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