Answer
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
Given,
∠BCE=28° ∠ACD=31° & line AB=AC .
According To the Question,
- a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°
- b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚
thus , ∠ABC=76° .
- c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,
Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°
Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)
∠DAB = 180° - 107° ⇔ 73°
& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°
Now, In Triangle ADC Sum of angles in a triangle is 180°
∠ADC = 180° - (31° + 45°) ⇔ 104˚
- d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre
For Diagram, Please Find in Attachment
Answer:
\[y = (-1/2) * x + 6\]
Step-by-step explanation:
Equation of the given line: y=2x+2
Hence the slope of the line is given by 2
Any line which is perpendicular to the given line will have a slope m such that m*2 = -1
Or, \[m = \frac{-1}{2}\]
Only options 2 and 3 satisfy this condition.
The line is also supposed to pass through the point (6,3).
Substituting these values in the option 2:
\[3 = (-1/2) * 6 + 3\]
Or, \[ 3 =0 \] which is false . Hence option 2 is not valid.
Now substituting (6,3) in option 3:
\[3 = (-1/2) * 6 + 6\]
Or, \[ 3 =3 \] which is true . Hence option 3 is the required equation of the line.
The <em><u>correct answer</u></em> is:
624 crayons.
Explanation:
In 12 of the boxes, 28 crayons have not been used; this leaves 64-28=36 crayons that have been used. 12(36) = 432 crayons have been used in these boxes.
3 full boxes have been used; this is 3(64) = 192 crayons.
Together this makes 432+192 = 624 crayons that have been used.