Answer:
Total money they had at first $252.
Step-by-step explanation:
Let,
x be the amount Silas had originally
y be the amount Raja had originally
According to given statement;
x = 3y Eqn 1
x - 84 = y + 42 Eqn 2
Putting x=3y in Eqn 2
3y - 84 = y + 42
3y - y = 42 + 84
2y = 126
Dividing both sides by 2
Putting y = 63 in Eqn 1
x = 3(63)
x = 189
Total money they originally had = 189 + 63 = $252
Hence,
Total money they had at first $252.
Interesting problem ...
The key is to realize that the wires have some distance to the ground, that does not change.
The pole does change. But the vertical height of the pole plus the distance from the pole to the wires is the distance ground to the wires all the time. In other words, for any angle one has:
D = L * sin(alpha) + d, where D is the distance wires-ground, L is the length of the pole, alpha is the angle, and 'd' is the distance from the top of the (inclined) pole to the wires:
L*sin(40) + 8 = L*sin(60) + 2, so one can get the length of the pole:
L = (8-2)/(sin(60) - sin(40)) = 6/0.2232 = 26.88 ft (be careful to have the calculator in degrees not rad)
So the pole is 26.88 ft long!
If the wires are higher than 26.88 ft, no problem. if they are below, the concerns are justified and it won't pass!
Your statement does not mention the distance between the wires and the ground. Do you have it?
Answer:
The product is 1.05
another pair of factors with the same product are 6/10 x 14/8
Answer:
i have no clue im sorry man but i need points. i hope someone helps you
Step-by-step explanation:
